字段中的错误数据

时间:2011-05-23 14:26:06

标签: java swing

这是我程序中的类的片段(我删除了一些不重要的代码)。首先,程序总是调用方法firstSet(),它在JPanel(板)上设置所有JLabel(玩家)。然后当我点击JLabel时,mouseClicked()运行方法findPlayer(),所以我知道选择了哪个JLabel。一切都好。

当我开始模拟时问题开始 - 方法simulationStart()运行10次。在此之后,当我点击播放器时,cmd行显示:I can't find it :(。我写了一些system.out来找出问题所在。问题出在locationXlocationY字段中,我不知道它们在findPlayer()simulationStart()中有何区别。

public class setBoard extends JFrame implements MouseListener {

    int[] locationX = new int[100];
    int[] locationY = new int[100];

    public void setLocation() {
        for (int i = 0; i < 100; i++) {
            locationX[i] = (int) (random() * (sizeX - xy));
            locationY[i] = (int) (random() * (sizeY - xy));
        }
    }

    public ArrayList<JLabel> firstSet() {
        setLocation();

        for (int i = 0; i < 100; i++) {
            player = new JLabel();

            //
            //some code to JLabel set
            //

            playerList.add(player);
            player.setBounds(locationX[i], locationY[i]);
            player.addMouseListener(this);
        }

        return playerList;
    }

    public ArrayList<JLabel> simulationStart(ArrayList<JLabel> playerList) {
        this.playerList = playerList;

        setLocation();

        for (int i = 0; i < 100; i++) {
            playerList.get(i).setBounds(locationX[i], locationY[i]);
            playerList.add(playerList.get(i));
        }
        return playerList;
    }

    public void mouseClicked(MouseEvent e) {     
        //
        //a lot of code to  search coursorX and coursorY, this works good
        //

        //if left mouse button 
        if (e.getButton() == 1) {
            final int playerNr = findPlayer(coursorX, coursorY);
            if (playerNr == -1) {
                System.out.println("I can`t find it :( ");
            }
            else{
                //
                //code to do when it find player
                //
            }
        }
    }

    //
    //
    //

    private int findPlayer(int x, int y) {
        int playerNr = -1;
        for (int i = 0; i < 100; i++) {
            if (x == locationX[i] && y == locationY[i]) {
                playerNr = i;
            }
        }
        return playerNr;
    }

}

1 个答案:

答案 0 :(得分:1)

每当你致电simulationStart时,你都会再次向playerList添加玩家。所以玩家数量超过100个。为什么不尝试打印出playerList的大小并检查它是否符合您的期望?

我认为您可能需要删除声明:playerList.add(playerList.get(i));