Question

我有两张桌子A（Utenti）e B（Dispositivi）;在B上有一个A的外键（一个Utente->许多Dispositivi）。我使用symfony管理生成器。我是否可以为每个Utente生成一个链接，该链接会在Dispositivi视图中列出我所有相关的Dispositivi。这有可能吗？

的schema.yml

   Dispositivi:
  connection: doctrine
  tableName: dispositivi
  columns:
    id_dispositivo:
      type: integer(4)
      fixed: false
      unsigned: false
      primary: true
      autoincrement: true
    device_id:
      type: string(255)
      fixed: false
      unsigned: false
      primary: false
      notnull: true
      autoincrement: false
    tipo:
      type: string(255)
      fixed: false
      unsigned: false
      primary: false
      notnull: true
      autoincrement: false
    utente_fk:
      type: integer(4)
      fixed: false
      unsigned: false
      primary: false
      notnull: true
      autoincrement: false
  relations:
    Utenti:
      local: utente_fk
      foreign: id_utente
      type: one
Utenti:
  connection: doctrine
  tableName: utenti
  columns:
    id_utente:
      type: integer(4)
      fixed: false
      unsigned: false
      primary: true
      autoincrement: true
    username:
      type: string(255)
      fixed: false
      unsigned: false
      primary: false
      notnull: true
      autoincrement: false
    password:
      type: string(255)
      fixed: false
      unsigned: false
      primary: false
      notnull: true
      autoincrement: false
    tipo:
      type: string(255)
      fixed: false
      unsigned: false
      primary: false
      notnull: true
      autoincrement: false
  relations:
    Dispositivi:
      local: id_utente
      foreign: utente_fk
      type: many
    Servizi:
      local: id_utente
      foreign: utente_fk
      type: many

Answer 1

以下是对学说代码的一个很好的参考：

http://redotheweb.com/2008/07/08/comparing-propel-doctrine-and-sfpropelfinder/ （特别是如果用来推动。）

首先，在generator.yml文件中添加一个部分。

然后做这样的事情：

<?php
    $dispositivis = $utente->Dispositivis;
?>

<?php foreach ($dispositivis as $d): ?>
    <?php echo link_to($d->getTipo(), 'module_name/action_name?id='. $d->getIdDispositivo()) ?><br />
<?php endforeach ?>

symfony外键一对多

1 个答案: