Question

          0            1    2
0  this           is  1.0
1    my         book  1.0
2  book         this  1.0
3    is           my  0.5
4    is  interesting  0.5

我的数据框看起来像这样，但是它是动态的。因此它也可能看起来像

      0     1            2    3
0  this    is  interesting  0.5
1    is    my         book  1.0
2  this    is           my  0.5
3    my  book         this  1.0
4  book  this           is  1.0

现在，我想从最后一列获取浮点值，以将前三列的值作为元组给出。像

("this","is") 
("this","is","interesting")

应该分别给我1.0和0.5的值。请帮我解决这个问题。

当前我正在使用

row = df[(df["0"] == "is") & (df["1"] == "my")]

但它不是动态的。

Answer 1

我不确定这是否是您想要的，看看是否可以根据您的需要进行修改：

 f = ("this","is","interesting")

#condition checks if words can be found in the dataframe
#looks for rows that has all the words
#and converts to an array of True or False
cond = df.iloc[:,:-1].isin(f).all(axis=1).to_numpy()

#filter the dataframe, to get the values from the last column 
#where condition is True
#iloc works with an array or list of Booleans,
#it cannot reference a series label,
#hence then need to convert the cond to a list or array
df.iloc[cond,-1]

0    0.5
Name: 3, dtype: float64

当然，您可以将结果分配给一列...但是我不确定这是否是您的

根据Pandas Dataframe中的其他单元格查找单元格值

1 个答案: