Question

我有这样的看法：

select Horse_Name, LevelName, TYPE_NAME, Event_Name, Result_Name
from V_Horse_Transaction

我的结果是这样的：

Horse_Name    LevelName   TYPE_NAME Result_Name
DXB-HORSE     QUALIFIER    40        PASS
DXB-HORSE     QUALIFIER    40        PASS
DXB-HORSE     QUALIFIER    80        PASS
DXB-HORSE     QUALIFIER    80        PASS
INDIAN-HORSE    QUALIFIER  40        FAIL
DXB-HORSE      QUALIFIER   40        PASS
INDIAN-HORSE    QUALIFIER  40         PASS
INDIAN-HORSE    QUALIFIER  80         FAIL
INDIAN-HORSE    QUALIFIER  80         FAIL

在我的查询中，我只想显示马名，该马名最少为2条记录（40条记录）和2条记录（80条记录），且两种结果类型均为“ Pass”（通行证）和LevelName ='QUALIFIER'。所以我写了这样的查询。但是我没有任何记录：我的查询是这样的：

select  Horse_Name, COUNT(2)
from V_Horse_Transaction
where TYPE_NAME = 40 and TYPE_NAME = 80
  and Result_Name = 'PASS' and LevelName = 'QUALIFIER' 
group by TYPE_NAME, Result_Name, LevelName, Horse_Name

Answer 1

您可以group by Horse_Name子句中having设置条件：

select Horse_Name
from V_Horse_Transaction
where TYPE_NAME in (40, 80) and Result_Name = 'PASS' and LevelName = 'QUALIFIER' 
group by Horse_Name
having count(case when TYPE_NAME = 40 then 1 end) >= 2
   and count(case when TYPE_NAME = 80 then 1 end) >= 2

请参见demo。
结果：

| Horse_Name |
| ---------- |
| DXB-HORSE  |

sql查询以检查至少2条记录是否存在

1 个答案: