Question

给出的是我创建为js文件的文件.....在我评论过的文件中单击按钮 output.js中的按钮标记工作正常，如果我在其他页面中更改按钮，则会造成混乱

output.js

import React, {Component} from 'react'
import { Modal, Button } from 'react-bootstrap'



class Threed extends Component {
    constructor(){
        super() 
        this.state ={show:false}
    }
    threedModal(){
        this.setState({show:!this.state.show})
    }
    render() {
        return (
            <div>
                {/*<Button onClick= {() => {this.threedModal()}}>
                    rajesh
        </Button>*/}
                <Modal show={this.state.show} onHide={() => this.handleModal()}>
                    <Modal.Header closeButton>MY popup</Modal.Header>
                    <Modal.Body>Rajesh modal done</Modal.Body>
                    <Modal.Footer><Button onClick= {() => {this.handleModal()}}> close </Button></Modal.Footer>
                </Modal>
            </div>
        )
    }

}
export default Threed

home.js

import React, {Component} from 'react'
import { Modal, Button } from 'react-bootstrap'
import threed from './output.js'


class Threed extends Component {
    constructor(){
        super() 
        this.state ={show:false}
    }
    threedModal(){
        this.setState({show:!this.state.show})
    }
    render() {
        return (
            <div>
              <Button onClick= {() => {this.threedModal()}}>
                    rajesh
        </Button>
           </div>
        )
    }

}
export default Threed

我想在单击home.js按钮的同时显示并显示模式弹出窗口…… 在这里，我的困惑是如何通过单击Home.js的按钮来实现这一功能

Answer 1

请将该值转发给模态。

Home.js

import Threed from './output.js'
class Home extends Component {

...
< Threed show={this.state.show} />

Threed.js

 <Modal show={this.props.show} onHide={() => this.handleModal()}>

如何在React中使用onclick按钮将另一个js文件输出调用到另一个js文件

1 个答案: