Unity2D-如何在2D游戏中围绕圆形移动和旋转游戏对象?

时间:2020-03-29 22:25:44

标签: c# unity3d

我正在尝试围绕目标行星(目前只是一个圆圈)移动和旋转一些云。我的机芯下降了,但是我真的在旋转部分上挣扎。我希望它与圆上的位置成比例旋转,但是我一直试图猜测正确的数字。这是代码:

public class CloudMovement : MonoBehaviour
{
    public GameObject target;
    private float RotateSpeed = .05f;
    private float Radius = 1.0f;

    private Vector2 center;
    private float angle;

    private void Start()
    {
        center = target.transform.localPosition;
        Radius = target.transform.localScale.x / 1.5f;
    }

    private void Update()
    {

        angle = angle + RotateSpeed * Time.deltaTime;
        this.transform.Rotate (Vector3.forward * -angle * Time.deltaTime);

        Vector2 offset = new Vector2(Mathf.Sin(angle), Mathf.Cos(angle)) * Radius;
        this.transform.position = center + offset;
    }
}

2 个答案:

答案 0 :(得分:3)

using UnityEngine;

public class CloudMovement : MonoBehaviour
{
    // X Y radius
    public Vector2 Velocity = new Vector2(1, 0); 

    // rotational direction
    public bool Clockwise = true;

    [Range(0, 5)] 
    public float RotateSpeed = 1f;
    [Range(0, 5)]
    public float RotateRadiusX = 1f;
    [Range(0, 5)]
    public float RotateRadiusY = 1f;        

    private Vector2 _centre;
    private float _angle;

    private void Start()
    {
        _centre = transform.position;
    }

    private void Update()
    {
        _centre += Velocity * Time.deltaTime;    
        _angle += (Clockwise ? RotateSpeed : -RotateSpeed) * Time.deltaTime;    
        var x = Mathf.Sin(_angle) * RotateRadiusX;
        var y = Mathf.Cos(_angle) * RotateRadiusY;    
        transform.position = _centre + new Vector2(x, y);
    }

    void OnDrawGizmos()
    {
        Gizmos.DrawSphere(_centre, 0.1f);
        Gizmos.DrawLine(_centre, transform.position);
    }
}

编辑选项2 RotateAround

一个最新的选项,嵌入到Unity 中-您也可以尝试使用RotateAround函数

Vector3 point = new Vector3(10,0,0);
Vector3 axis =  new Vector3(0,0,1);
transform.RotateAround(point, axis, Time.deltaTime * 10);

轴是旋转方向。


同一件事,带有一个有效的示例from here

transform.RotateAround()

答案 1 :(得分:0)

你可以!通过不断改变 x 比例!在更新 void 中调用这个函数

public void Rotate()
    {
        if (transform.localScale.x <= -1)
        {
            rotationBool = true;
        }
        if (transform.localScale.x >= 1)
        {
            rotationBool = false;
        }
        if (rotationBool == false)
        {
            Vector3 scaleChange = new Vector3(0.01f, 0f, 0f);
            transform.localScale -= scaleChange;
        }
        if (rotationBool == true)
        {
            Vector3 scaleChange = new Vector3(0.01f, 0f, 0f);
            transform.localScale += scaleChange;
        }
    }