请帮我把这个伪代码翻译成真正的PHP代码:
foreach ($arr as $k => $v)
if ( THIS IS NOT THE LAST ELEMENT IN THE ARRAY)
doSomething();
编辑:数组可能包含数字或字符串键
答案 0 :(得分:111)
您可以使用PHP的end()
$array = array('a' => 1,'b' => 2,'c' => 3);
$lastElement = end($array);
foreach($array as $k => $v) {
echo $v . '<br/>';
if($v == $lastElement) {
// 'you can do something here as this condition states it just entered last element of an array';
}
}
<强> UPDATE1 强>
正如@Mijoja所指出的,如果你在数组中多次使用相同的值,那么上面可能会有问题。下面是它的修复。
$array = array('a' => 1, 'b' => 2, 'c' => 3, 'd' => 2);
//point to end of the array
end($array);
//fetch key of the last element of the array.
$lastElementKey = key($array);
//iterate the array
foreach($array as $k => $v) {
if($k == $lastElementKey) {
//during array iteration this condition states the last element.
}
}
<强> UPDATE2 强>
我发现@onteria_的解决方案比我回答的更好,因为它没有修改数组内部指针,我正在更新答案以匹配他的答案。
$array = array('a' => 1, 'b' => 2, 'c' => 3, 'd' => 2);
// Get array keys
$arrayKeys = array_keys($array);
// Fetch last array key
$lastArrayKey = array_pop($arrayKeys);
//iterate array
foreach($array as $k => $v) {
if($k == $lastArrayKey) {
//during array iteration this condition states the last element.
}
}
谢谢@onteria _
答案 1 :(得分:19)
这对我来说总是有把戏
foreach($array as $key => $value) {
if (end(array_keys($array)) == $key)
// Last key reached
}
编辑30/04/15
$last_key = end(array_keys($array));
reset($array);
foreach($array as $key => $value) {
if ( $key == $last_key)
// Last key reached
}
避免@Warren Sergent提到的E_STRICT警告
$array_keys = array_keys($array);
$last_key = end($array_keys);
答案 2 :(得分:12)
$myarray = array(
'test1' => 'foo',
'test2' => 'bar',
'test3' => 'baz',
'test4' => 'waldo'
);
$myarray2 = array(
'foo',
'bar',
'baz',
'waldo'
);
// Get the last array_key
$last = array_pop(array_keys($myarray));
foreach($myarray as $key => $value) {
if($key != $last) {
echo "$key -> $value\n";
}
}
// Get the last array_key
$last = array_pop(array_keys($myarray2));
foreach($myarray2 as $key => $value) {
if($key != $last) {
echo "$key -> $value\n";
}
}
由于array_pop
适用于array_keys
创建的临时数组,因此根本不会修改原始数组。
$ php test.php
test1 -> foo
test2 -> bar
test3 -> baz
0 -> foo
1 -> bar
2 -> baz
答案 3 :(得分:4)
为什么不是这个非常简单的方法:
$i = 0; //a counter to track which element we are at
foreach($array as $index => $value) {
$i++;
if( $i == sizeof($array) ){
//we are at the last element of the array
}
}
答案 4 :(得分:2)
我知道这是旧的,使用SPL迭代器可能只是一种矫枉过正,但无论如何,这里有另一种解决方案:
$ary = array(1, 2, 3, 4, 'last');
$ary = new ArrayIterator($ary);
$ary = new CachingIterator($ary);
foreach ($ary as $each) {
if (!$ary->hasNext()) { // we chain ArrayIterator and CachingIterator
// just to use this `hasNext()` method to see
// if this is the last element
echo $each;
}
}
答案 5 :(得分:1)
我的解决方案,也很简单..
$array = [...];
$last = count($array) - 1;
foreach($array as $index => $value)
{
if($index == $last)
// this is last array
else
// this is not last array
}
答案 6 :(得分:0)
如果项目按数字顺序排序,请使用key()函数确定当前项目的索引并将其与长度进行比较。你必须使用next()或prev()循环while循环中的项而不是for循环:
$length = sizeOf($arr);
while (key(current($arr)) != $length-1) {
$v = current($arr); doSomething($v); //do something if not the last item
next($myArray); //set pointer to next item
}
答案 7 :(得分:0)
$arr = array(1, 'a', 3, 4 => 1, 'b' => 1);
foreach ($arr as $key => $val) {
echo "{$key} = {$val}" . (end(array_keys($arr))===$key ? '' : ', ');
}
// output: 0 = 1, 1 = a, 2 = 3, 4 = 1, b = 1
答案 8 :(得分:0)
成功了
$lastKey = array_key_last($array);
foreach($array as $k => $v) {
echo $v . '<br/>';
if($k == $lastKey) {
// 'you can do something here as this condition states it just entered last element of an array';
}
}
答案 9 :(得分:0)
使用 array_keys
函数获取键的简单方法,并且仅获取反向数组的第一个键 [0]
,即最后一个键。< /p>
$array = array('a' => 1,'b' => 2,'c' => 3);
$last_key = array_keys(array_reverse($array, true))[0];
foreach($array as $key => $value) {
if ($last_key !== $key)
// THIS IS NOT THE LAST ELEMENT IN THE ARRAY doSomething();
}
注意:array_reverse
反向数组采用两个参数,第一个数组我们想要颠倒,第二个参数为真,以反转数组并保留键的顺序 .