SQL Query获取列表中每个元素的前1个值

Question

我需要帮助编写一个返回所有列的查询

select id, city, road1, road2, lat, long 
from tbltest 
group by id, city, lat, long. 

最终结果应该是这样的

谢谢， 爬完

Answer 1

虽然很奇怪，但是这里的表有重复的id列，这个查询会显示你需要的结果：

select id, city, road1, road2, lat, long
from
(
    select *, row_number() over(partition by id, city, lat, long order by road1, road2) RowNumber
    from tbltest 
) tt
where RowNumber = 1

Answer 2

Using Common Table Expressions

;with tbl as
(
    select *, row_number() over(partition by id, city order by road1, road2) RowNumber
    from tbltest 
)

select * from tbl
where RowNumber = 1