如何跳过与正则表达式的匹配

Question

如何跳过与正则表达式的匹配，我想获得ss并跳过=

代码：

var patt = new RegExp("=ss","g");
var url = "https://mass.lass.com/?t=ss";
var x = url.match(patt);
console.log(x);

//result
=ss

i only need SS

Answer 1

使用积极的眼神。代替

new RegExp("=ss","g")

您可以使用

new RegExp("(?<==)ss", "g")

Answer 2

尝试使用此功能（更通用），它使用params和url作为参数

 

const url = "https://mass.lass.com/?t=ss";

const getQueryParams = ( url, params ) => {
  let reg = new RegExp( '[?&]' + params + '=([^&#]*)', 'i' );
  let queryString = reg.exec(url);
  return queryString ? queryString[1] : null;
};

console.log(getQueryParams(url, "t"))