我正在使用显示带有反应的Google地图的应用程序Google Maps已安装了多个图钉,并且通过滚动来更改状态,并且活动航班会根据状态进行更改。
当时,Google地图的中心设置为活动,但是状态改变时会重新渲染Google地图。我不知道如何防止渲染。
Google Maps has NPM library。它使用react-google-maps并使用钩子实现。我试图使用useEffect()返回false,但是我没有听到它的原样。请告诉我
MapComponent(HOC)
import React from "react";
import { withGoogleMap, GoogleMap, withScriptjs, Marker, InfoWindow } from "react-google-maps";
import { compose, withProps, withHandlers, withStateHandlers } from "recompose";
const MapWithPlaces = compose(
withProps({
googleMapURL:
`https://maps.googleapis.com/maps/api/js?key=${process.env.REACT_APP_GOOGLE_PLACE_API_KEY}&libraries=geometry,drawing,places`,
loadingElement: <div style={{ height: `100%` }} />,
containerElement: <div style={{ height: "400px", width: "100%" }} />,
mapElement: <div style={{ height: "100%" }} />
}),
withStateHandlers(
props => ({
infoWindows: props.places.map(p => {
return { isOpen: false };
}),
defaultCenter: { 'lat': props.lat, 'lng': props.lng }
}),
{
onToggleOpen: ({ infoWindows }) => selectedIndex => ({
infoWindows: infoWindows.map((iw, i) => {
iw.isOpen = selectedIndex === i;
return iw;
})
})
}
),
withHandlers(() => {
const refs = {
map: undefined,
}
console.log(refs);
return {
onMapMounted: () => ref => {
refs.map = ref
},
onZoomChanged: ({ onZoomChange }) => (props) => {
const center = { 'lat': parseFloat(props.lat, 10), 'lng': parseFloat(props.lng, 10) }
refs.map.pantTo(center)
}
}
}),
withScriptjs,
withGoogleMap
)(props => (
<GoogleMap defaultZoom={props.zoom} defaultCenter={props.center} key={props.key} ref={map}>
{props.places &&
props.places.map((place, i) => {
let lat = parseFloat(place.lat, 10);
let lng = parseFloat(place.lng, 10);
return (
<Marker
id={place.id}
key={place.key}
position={{ lat: lat, lng: lng }}
title={place.name}
onClick={props.onToggleOpen.bind(this, i)}
opacity={place.key === props.step ? 1 : 0.5}
label={place.day === props.currentDay ? place.dayIndex.toString() : ''}
>
{props.infoWindows[i].isOpen && (
<InfoWindow onCloseClick={props.onToggleOpen.bind(i)}>
<div>{place.name}</div>
</InfoWindow>
)}
</Marker>
);
})}
</GoogleMap>
));
export default MapWithPlaces;
MapComponent(挂钩)
import React, { useState, useEffect, useRef } from "react";
import { withGoogleMap, withScriptjs, GoogleMap, Marker, InfoWindow } from "react-google-maps";
// import mapStyles from "./mapStyles";
const MapCreate = React.memo((props) => {
// const [selectedPark, setSelectedPark] = useState(null);
const mapRef = useRef()
useEffect(() => {
console.log("props updates")
console.log(props);
const mapCenter = {
lat: parseFloat(props.places[props.step].lat, 10),
lng: parseFloat(props.places[props.step].lng, 10)
}
return false
// refMap.current.panTo(mapCenter) //move the map to new location
}, [props]);
return (
<GoogleMap defaultZoom={14} center={{ lat: props.center.lat, lng: props.center.lng }} ref={mapRef}>
{props.places && props.places.map((place, i) => {
let lat = parseFloat(place.lat, 10);
let lng = parseFloat(place.lng, 10);
return (
<Marker
id={place.id}
key={place.key}
position={{ lat: lat, lng: lng }}
title={place.name}
opacity={place.key === props.step ? 1 : 0.5}
label={place.day === props.currentDay ? place.dayIndex.toString() : ''}
>
</Marker>
)
})}
</GoogleMap>
)
})
const MapWrapped = withScriptjs(withGoogleMap(MapCreate));
export default function Map(props) {
const mapRef = useRef(null)
return (
<div style={{ width: "100%", height: "400px" }}>
<MapWrapped
googleMapURL={`https://maps.googleapis.com/maps/api/js?v=3.exp&libraries=geometry,drawing,places&key=${process.env.REACT_APP_GOOGLE_PLACE_API_KEY}`}
loadingElement={<div style={{ height: `100%` }} />}
containerElement={<div style={{ height: "400px", width: "100%" }} />}
mapElement={<div style={{ height: `100%` }} />}
{...props}
/>
</div>
);
}
答案 0 :(得分:0)
shouldComponentUpdate(nextProps, nextState)
使用shouldComponentUpdate()来让React知道组件的输出是否 不受当前状态或道具变更的影响。默认值 行为是在每一个状态变化时以及在广大 大多数情况下,您应该依靠默认行为。
应该在呈现新道具或新道具之前调用
shouldComponentUpdate() 状态正在接收。默认为true。此方法未调用 初始渲染或使用forceUpdate()时