我有这段代码可以在标题中显示菜单,但我想显示所选类别页面的子类别,而不是父类别。
<?php
$categories = get_the_category();
$category_id = $categories[0]->cat_ID;
foreach ( $category_id as $navItem ) {
$class_names = $value = '';
$classes = empty( $navItem->classes ) ? array() : (array) $navItem->classes;
$classes[] = 'menu-item-' . $navItem->ID;
$class_names = join( ' ', apply_filters( 'nav_menu_css_class', array_filter( $classes ), $navItem ) );
if ( in_array( 'current-menu-item', $classes ) )
$class_names .= ' active';
$class_names = $class_names ? ' class="' . esc_attr( $class_names ) . '"' : '';
$id = apply_filters( 'nav_menu_item_id', 'menu-item-'. $navItem->ID, $navItem );
$id = $id ? ' id="' . esc_attr( $id ) . '"' : '';
echo '<li ' . $id . ' ' . $class_names . '><a href="'.$navItem->url.'" title="'.$navItem->title.'">'.$navItem->title.'</a></li>';
}
?>
谢谢
答案 0 :(得分:0)
好吧,我进行了一些搜索,然后就可以解决这个问题
这是代码
<?php
if(is_category() && the_category_ID(false) != NULL)
{
$categories = get_categories(array("child_of" => the_category_ID(false), "hide_empty" => 0));
foreach ($categories as $category)
{
$class_names = $value = '';
$classes = (array) $navitem ='';
$classes[] = 'menu-item-' . $category->cat_ID;
$class_names = join( ' ', apply_filters( 'nav_menu_css_class', array_filter( $classes ), $category ) );
if ( in_array( 'current-menu-item', $classes ) )
$class_names .= ' active';
$class_names = $class_names ? ' class="' . esc_attr( $class_names ) . '"' : '';
$id = apply_filters( 'nav_menu_item_id', 'menu-item-'. $category->cat_ID, $category );
$id = $id ? ' id="' . esc_attr( $id ) . '"' : '';
echo '<li ' . $id . ' ' . $class_names . '><a href="'.get_bloginfo("url") .'/category/' .$category->slug.'" title="'.$category->cat_name.'">'.$category->cat_name.'</a></li>';
}
}
?>
希望它对某人也有帮助
the_category_ID()
这是获取当前页面类别的ID,我们使用false,因此不会打印ID
然后循环进入子类别或子类别,并获取其名称+网址的子弹