Question

我正在用Python执行一项任务，即根据输入的月份和月份中的某天来创建一个十二生肖日历。

我制作了一个成功的日历，但是，如果我输入了错误的月份名称或不存在的日期，我不知道如何解决该问题。

我尝试了很多事情：创建不同的层次结构，或者在我写的else: print ('Entering an incorrect date')的每个十二生肖下。我什至试图用if day <0 and day> 31 or month! = 'March' or month! = 'April'进行注册，等等……最终结果是一个巨大的无用功能，也没有任何作用。

我觉得这里有一种单行解决方案，可以检测到<0和> 31天以及不正确的月份名称，但是我听不懂。有人可以帮忙吗？

month = input('Enter the month: ')
day = int(input ('Enter the date of month: '))
if day >= 21 and day <= 31 and month.lower() == 'march' or day >=1 and day <= 19 and month.lower() == 'april':
    zodiac='Aries'
if day >= 20 and day <= 30 and month.lower() == 'april' or day >=1 and day <= 19 and month.lower() == 'may':
    zodiac='Taurus'
if day >= 21 and day <= 31 and month.lower() == 'may' or day >=1 and day <= 20 and month.lower() == 'june':
    zodiac='Gemini'
if day >= 21 and day <= 30 and month.lower() == 'june' or day >=1 and day <= 22 and month.lower() == 'july':
    zodiac='Cancer'
if day >= 23 and day <= 31 and month.lower() == 'july' or day >=1 and day <= 22 and month.lower() == 'august':
    zodiac='Leo'
if day >= 23 and day <= 31 and month.lower() == 'august' or day >=1 and day <= 22 and month.lower() == 'september':
    zodiac='Virgo'
if day >= 23 and day <= 30 and month.lower() == 'september' or day >=1 and day <= 22 and month.lower() == 'october':
    zodiac='Libra'
if day >= 23 and day <= 31 and month.lower() == 'october' or day >=1 and day <= 21 and month.lower() == 'november':
    zodiac='Scorpio'
if day >= 22 and day <= 30 and month.lower() == 'november' or day >=1 and day <= 21 and month.lower() == 'december':
    zodiac='Sagittarius'
if day >= 22 and day <= 31 and month.lower() == 'december' or day >=1 and day <= 19 and month.lower() == 'january':
    zodiac='Capricorn'
if day >= 20 and day <= 31 and month.lower() == 'january' or day >=1 and day <= 18 and month.lower() == 'february':
    zodiac='Aquarius'
if day >= 19 and day <= 28 and month.lower() == 'february' or day >=1 and day <= 20 and month.lower() == 'march':
    zodiac='Pisces'  
print('Conclusion:')
print(zodiac)

Answer 1

您可能想研究datetime模块。有了它，您可以轻松地在日期和时间之间进行比较，而无需多余的if语句。

例如，如果要执行以下操作：

import datetime
dt = datetime.datetime.today()
print dt.month

那么您会得到：

因此，您不必索要以字符串格式输入数月的信息，只需索要月份的数字即可帮助更轻松地创建datetime对象。或者，您可以执行以下操作：

month_input = input("What is the month?")
months = ["january", "february", "march", "april", "may", "june", "july", "august", "september", "october", "november", "december"]
month_input = month_input.lower().strip() #convert to lowercase and remove whitespace
month_num = months.index(month_input) + 1 #Add one because lists start at index 0

这样，您可以获取使用datetime对象从那里进行比较和评估的月份数。

十二生肖日历样本中日期的意外输入值检测

1 个答案: