C ++“双精度”值之间的差异与预期值不匹配

Question

考虑以下代码：

#include <iostream>
using namespace std;

int main() {
    double x = 1.77;
    double y = 1.76;

    double diff = x-y;
    cout << "x-y = " << diff << endl;
    if (diff <= 0.01)
    {
        cout << "x and y differ by less than 1.0/100 ..." << endl;
    }
    return 0;
}

以下是我得到的输出：

x-y = 0.01

但是我在这里看不到打印的x and y differ by less than 1.0/100...，预期，因为x和y之间的差是0.01。