Question

我有2个对象：

Obj1 = {
  0: "AS1",
  1: "AS2",
  2: "AS3"
}


Obj2 = {
  AS1: "Hani"
  AS2: "Joe"
}

我想将Obj1的值与Obj2的键进行比较，并打印Obj2的值。

Answer 1

您可以使用一个值为obj1的数组，并迭代obj2的键。

var obj1 = { 0: "AS1", 1: "AS2", 2: "AS3" },
    obj2 = { AS1: "Hani", AS2: "Joe" },
    result = Object.assign([], obj1).map(k => k in obj2 ? obj2[k] : null);

console.log(result);

Answer 2

我不确定您想要实现什么，但是您可以像这样访问所需的值：

let Obj1values = Object.values(Obj1);

console.log(Obj1values)

let Obj2Keys = Object.keys(Obj2);

console.log(Obj2Keys)

Answer 3

let ob1 = {0: "AS1", 1: "AS2", 2: "AS3" }

let ob2 = {AS1: "Hani", AS2: "Joe" }

let ob1Vals = Object.values(ob1)
let ob2Keys = Object.keys(ob2)

console.log(ob1Vals, ob2Keys)

ob2Keys.forEach(e => {
    if(ob1Vals.includes(e)) {
        console.log(ob2[e])
    }
})

Answer 4

这基本上等同于Excel的VLOOKUP函数（没有精确匹配选项）。

通过当前User的值搜索源对象，然后返回Name的值。由于这是标量值，因此不需要字段/索引。

const lookup = (value, source, field) => {
  return ((match) => {
    return match && field ? match[field] : match || null;
  })(source[value]);
}

let Users = {
  0: "AS1",
  1: "AS2",
  2: "AS3"
}

let Names = {
  AS1: "Hani",
  AS2: "Joe"
}

console.log(Object.keys(Users).map(id => {
  return lookup(Users[id], Names);
}));

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比较2个对象的值和键

4 个答案: