请注意,如果“if(true)”未切换为false,则不会呈现任何内容。换句话说,如果传递给数据网格构造函数的父节点是innerHTML元素id,为什么没有渲染。如果是这样的话,有人能告诉我怎么做吗?
@import "dojo/dijit/themes/tundra/tundra.css";
@import "dojo/dojox/grid/resources/Grid.css";
@import "dojo/resources/dojo.css"
dojo.require("dijit._Widget");
dojo.require("dijit._Templated");
dojo.require("dojox.grid.DataGrid");
dojo.require("dojo.data.ItemFileReadStore");
dojo.addOnLoad(function()
{
dojo.require('dojo.parser');
});
dojo.ready(function()
{
dojo.parser.parse();
var top = "root";
if (true) // ';
dojo.parser.parse();
top = "first";
}
// Create the data grid parameters.
var layout =
[
{ name: 'Name', field: 'name', width: '100px' },
{ name: 'Color', field: 'color', width: '100px' }
];
var dataStore =
{
data :
{
items :
[
{ name : 'John Doe', color: 'green' },
{ name : 'Jane Doe', color: 'red' }
]
}
};
var grid = new dojox.grid.DataGrid
(
{
store: new dojo.data.ItemFileReadStore(dataStore),
clientSort: true,
structure: layout
},
dojo.byId(top)
);
grid.startup();
});
答案 0 :(得分:0)
HTML:
<div id="top"></div>
的javascript:
dojo.require("dijit._Widget");
dojo.require("dijit._Templated");
dojo.require("dojox.grid.DataGrid");
dojo.require("dojo.data.ItemFileReadStore");
dojo.require('dojo.parser');
dojo.ready(function()
{
// Create the data grid parameters.
var layout =
[
{ name: 'Name', field: 'name', width: '100px' },
{ name: 'Color', field: 'color', width: '100px' }
];
var dataStore = {
data :
{items :[
{ name : 'John Doe', color: 'green' },
{ name : 'Jane Doe', color: 'red' }
],
label:'name',
identifier:'color'
}
};
var grid = new dojox.grid.DataGrid
(
{
store: new dojo.data.ItemFileReadStore(dataStore),
clientSort: true,
structure: layout
},
"top" // this id should be there in HTML .
);
});