Question

我正在尝试使用Selenium：https://results.decisiondeskhq.com/2020/primary/colorado/president单击此网站上的“登录”按钮。我右键单击了inspect元素中的元素，复制了xpath，并将其放入find_element_by_xpath函数中。

这是我的代码：

from selenium import webdriver

driver = webdriver.Chrome(executable_path="/users/aliallam/Desktop/scraper test/chromedriver")
url = 'https://results.decisiondeskhq.com/2020/primary/colorado/president'
driver.get(url)

driver.find_element_by_xpath('//*[@id="content"]/div/div/div/div/button').click()

这是我收到的错误消息：

Traceback (most recent call last):
  File "/Users/aliallam/Desktop/scraper test/sandbox2.py", line 7, in <module>
    driver.find_element_by_xpath('//*[@id="content"]/div/div/div/div/button').click()
  File "/Library/Frameworks/Python.framework/Versions/3.8/lib/python3.8/site-packages/selenium/webdriver/remote/webdriver.py", line 394, in find_element_by_xpath
    return self.find_element(by=By.XPATH, value=xpath)
  File "/Library/Frameworks/Python.framework/Versions/3.8/lib/python3.8/site-packages/selenium/webdriver/remote/webdriver.py", line 976, in find_element
    return self.execute(Command.FIND_ELEMENT, {
  File "/Library/Frameworks/Python.framework/Versions/3.8/lib/python3.8/site-packages/selenium/webdriver/remote/webdriver.py", line 321, in execute
    self.error_handler.check_response(response)
  File "/Library/Frameworks/Python.framework/Versions/3.8/lib/python3.8/site-packages/selenium/webdriver/remote/errorhandler.py", line 242, in check_response
    raise exception_class(message, screen, stacktrace)
selenium.common.exceptions.NoSuchElementException: Message: no such element: Unable to locate element: {"method":"xpath","selector":"//*[@id="content"]/div/div/div/div/button"}
  (Session info: chrome=80.0.3987.149)

提前谢谢！

Answer 1

该元素具有唯一的ID，因此应该使用ID而不是使用xpath，并且应该对元素进行显式等待，以便脚本等待直到该元素存在并且上面存在div元素您要单击的元素，在这种情况下需要使用Java脚本单击。
您的代码应类似于：

from selenium import webdriver
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.common.by import By
from selenium.webdriver.support import expected_conditions as EC

driver = webdriver.Chrome(executable_path="/users/aliallam/Desktop/scraper test/chromedriver")
url = 'https://results.decisiondeskhq.com/2020/primary/colorado/president'
driver.get(url)

element = WebDriverWait(driver, 20).until(EC.presence_of_element_located((By.ID, "login-text-btn")))
driver.execute_script("arguments[0].click();", element)

Answer 2

您需要等到网页加载后才能选择按钮。您需要导入

from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC
from selenium.webdriver.common.by import By

添加延迟，然后等待，然后再选择以下元素：

delay = 10  # seconds
WebDriverWait(driver, delay).until(
    EC.presence_of_element_located((By.CLASS_NAME, 'signup-boxes')))
# you can select element that you want ini here

有关更多资源，请访问here

硒找不到链接元素

2 个答案: