android上的tcp套接字问题

时间:2011-05-20 20:10:57

标签: android

我需要使用tcp套接字连接来获取蓝盒中的数据,如果我输入注释,例如“getcolor”,蓝盒会向我发送“红色,蓝色”等信息。 在这种情况下,bluebox作为服务器,我不需要对它进行编程,但是我有问题在EditText上显示信息。

public class sender {
public static void main(String[] args)throws IOException{

        Socket socket = new Socket("192.168.1.176",14111);

        OutputStream out = socket.getOutputStream();

        BufferedReader msg = new BufferedReader(new InputStreamReader(System.in)); 
        BufferedReader in = new BufferedReader(new InputStreamReader(socket.getInputStream()));         
         PrintWriter ou = new PrintWriter(new BufferedWriter(new OutputStreamWriter(out)),true);

         String buffer = new String("");
         String ms = "";
      while(true)
      {
          while(in.ready())

              buffer+= in.readLine()+ "\n";
          String[] line = buffer.split("\n");

          while(msg.ready())
              ms = msg.readLine();
          if(ms.equals("exit"))
          {
              break;
          }
          if(!ms.equals(""))
          {
              ou.println(ms);
              ou.flush();
              ms = "";
          }
          if(!buffer.equals(""))
          {

              System.out.print(buffer);
              buffer = "";

          }

      } 

      in.close();
      out.close();
      socket.close();

}
}

这个java代码有效,但在下面的android代码中失败了:

public class BlueBoxApp extends Activity {
/** Called when the activity is first created. */

Context appInstance = this;
private EditText info;
@Override
public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
           info = (EditText)findViewById(R.id.EditText01);
    try{

        InetAddress serverAddr = InetAddress.getByName("192.168.1.176");//TCP服务器IP地址

            Log.d("TCP", "server,receiving...");

          Socket socket = new Socket(serverAddr,14111);


           try {   


           OutputStream out = socket.getOutputStream();
           BufferedReader msg = new BufferedReader(new InputStreamReader(System.in)); 
           BufferedReader in = new BufferedReader(new InputStreamReader(socket.getInputStream()));          
         PrintWriter ou = new PrintWriter(new BufferedWriter(new OutputStreamWriter(out)),true);

            String buffer = new String("");
            String ms = "getsensorno";
            Log.d("TCP", "sending:'"+ms+"'");
        while(true)
        {
          while(in.ready())

              buffer+= in.readLine()+ "\n";

          while(msg.ready())
              ms = msg.readLine();
          if(ms.equals("exit"))
          {
              break;
          }
          if(!ms.equals(""))
          {
              ou.println(ms);
              ou.flush();
              ms = "";
          }
          if(!buffer.equals(""))
          {

             info.setText(buffer);
            buffer = "";

          } 
        } 

            } catch (Exception e) {

            Log.e("TCP", "error",e);

        }finally{

            socket.close();

        }

        }catch(Exception e){

           Log.e("TCP", "error",e);

        }
}
}

问题是什么以及如何为它设置线程?谢谢!

1 个答案:

答案 0 :(得分:3)

正如您所指出的,问题在于您正在主线程上执行网络部分。

设置新线程很简单,请考虑使用AsyncTask。在开始实现它之前,请阅读文档(这是非常好的),这将使恕我直言更容易。

另外,请确保您在 AndroidManifest.xml

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