此bash命令“ SELECT ZMATNR, ZLPN
FROM tblZMMGPNXREF
WHERE ZMATNR IN ('89187605', '89363059');
”返回UTC或系统时间类型。现在我想用它来将时间转换成相同的格式。我怎样才能做到这一点?
我尝试过此操作,但它无法运行td-agent。
etcdctl get system config/log/timestamp
现在我想使用该timeType将我的时间从给定日志转换为该timeType
<source>
@type exec
command etcdctl get system config/log/timestamp
<parse>
keys timeType
</parse>
</source>
这是我要使用该$ timeType的地方
{"host":"sp-1","level":"INFO","log":{"classname":"common.server.hacluster.CSFHATopologyChangeHandlerMBean:93","message":"Finished processing CSF HA 'become standby' message.","stacktrace":"","threadname":"RMI TCP Connection(1784)-192.168.20.11"},"process":"becomeStandby","service":"SP","time":"2020-03-19T10:15:36.514Z","timezone":"America/Toronto","type":"log","system":"SP_IG_20_3_R1_I2002","systemid":"SP_IG_20_3_R1_I2002"}
答案 0 :(得分:0)
使用记录修饰符的prepare_value解决了该问题
<filter com.logging.tmplog>
@type record_modifier
prepare_value @timeType =
`etcdctl获取系统配置/日志/时间戳`.strip
<record>
timeType ${@timeType}
time ${if @timeType == 'UTC' then Time.at(time).utc.strftime('%FT%T') else Time.at(time).to_s; end}
</record>
</filter>