我有一个拆分分隔列表的视图。例如,如果您的下表包含以下两列:
ABC, A;B;C
假设名称为“TestView”,您将获得以下内容:
Label Source
--------------
ABC A
ABC B
ABC C
代码源自此处:Split one column into multiple rows
当我尝试在视图的where子句中放入一个条件时,我收到一个错误。 “传递给LEFT或SUBSTRING函数的长度参数无效。”所以任何类似“从TestView中选择*来源='A'”都会导致错误。
以下是视图中的代码:
CREATE VIEW [dbo].[TestView]
AS
WITH L0 AS (SELECT 1 AS c
UNION ALL
SELECT 1),
L1 AS (SELECT 1 AS c
FROM L0 AS A,
L0 AS B),
L2 AS (SELECT 1 AS c
FROM L1 AS A,
L1 AS B),
L3 AS (SELECT 1 AS c
FROM L2 AS A,
L2 AS B),
--counts up to 256
Numbers AS (SELECT ROW_NUMBER() OVER (ORDER BY c) AS n
FROM L3)
SELECT Label,
LTRIM(RTRIM(SUBSTRING(valueTable.Sources, nums.n, charindex(N';', valueTable.Sources + N';', nums.n) - nums.n))) AS Source
FROM Numbers AS nums
JOIN dbo.SourceTable AS valueTable ON nums.n <= CONVERT(int, LEN(valueTable.Sources))
AND SUBSTRING(N';' + valueTable.Sources, n, 1) = N';'
答案 0 :(得分:1)
无效长度参数通常意味着您将负值传递给子字符串函数。
找出每件唱片的结果: charindex(N';',valueTable.Sources + N';',nums.n) - nums.n
我敢打赌,charindex返回0表示找不到该值,nums.n大于0。
答案 1 :(得分:1)
该链接提供了另一篇文章(http://www.sqlservercentral.com/articles/Tally+Table/72993/)的链接,该文章提供了一个非常高性能的分割器功能。
您可以尝试使用此
CREATE FUNCTION dbo.DelimitedSplit8K
--===== Define I/O parameters
(@pString VARCHAR(8000), @pDelimiter CHAR(1))
RETURNS TABLE WITH SCHEMABINDING AS
RETURN
--===== "Inline" CTE Driven "Tally Table" produces values from 0 up to 10,000...
-- enough to cover VARCHAR(8000)
WITH E1(N) AS (
SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL
SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL
SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1
), --10E+1 or 10 rows
E2(N) AS (SELECT 1 FROM E1 a, E1 b), --10E+2 or 100 rows
E4(N) AS (SELECT 1 FROM E2 a, E2 b), --10E+4 or 10,000 rows max
cteTally(N) AS (--==== This provides the "zero base" and limits the number of rows right up front
-- for both a performance gain and prevention of accidental "overruns"
SELECT 0 UNION ALL
SELECT TOP (DATALENGTH(ISNULL(@pString,1))) ROW_NUMBER() OVER (ORDER BY (SELECT NULL)) FROM E4
),
cteStart(N1) AS (--==== This returns N+1 (starting position of each "element" just once for each delimiter)
SELECT t.N+1
FROM cteTally t
WHERE (SUBSTRING(@pString,t.N,1) = @pDelimiter OR t.N = 0)
)
--===== Do the actual split. The ISNULL/NULLIF combo handles the length for the final element when no delimiter is found.
SELECT ItemNumber = ROW_NUMBER() OVER(ORDER BY s.N1),
Item = SUBSTRING(@pString,s.N1,ISNULL(NULLIF(CHARINDEX(@pDelimiter,@pString,s.N1),0)-s.N1,8000))
FROM cteStart s
;
然后就是
的情况with rawData (Label,rawString) as (select 'ABC','A;B;C')
select Label,Item From rawData
Cross Apply DelimitedSplit8K(rawData.rawString, ';')
WHERE Item = 'A'