如果我的应用程序位于http://sitename.com/myapp/并且我想通过url传递一个变量(即 - http://sitename.com/myapp/?name=Joe),我怎样才能将该名称变量转换为字符串var?
答案 0 :(得分:3)
我使用Adobe提供的in this article类。
package
{
import flash.external.*;
import flash.utils.*;
public class QueryString
{
private var _queryString:String;
private var _all:String;
private var _params:Object;
public function get queryString():String
{
return _queryString;
}
public function get url():String
{
return _all;
}
public function get parameters():Object
{
return _params;
}
public function QueryString()
{
readQueryString();
}
private function readQueryString():void
{
_params = {};
try
{
_all =
ExternalInterface.call("window.location.href.toString");
_queryString =
ExternalInterface.call("window.location.search.substring", 1);
if(_queryString)
{
var params:Array = _queryString.split('&');
var length:uint = params.length;
for (var i:uint=0,index:int=-1; i 0)
{
var key:String = kvPair.substring(0,index);
var value:String = kvPair.substring(index+1);
_params[key] = value;
}
}
}
}catch(e:Error) { trace("Some error occured.
ExternalInterface doesn't work in Standalone player."); }
}
}
}
更新:此类的更新版本也可以be found here,但我还没有尝试过这个版本。
更新2: 这是一个关于如何使用Querystring类的示例:
public function CheckForIDInQuerystring():void
{
// sample URL: http://www.mysite.com/index.aspx?id=12345
var qs:QueryString = new QueryString;
if (qs.parameters.id != null)
{
// URL contains the "id" parameter
trace(qs.parameters.id);
}
else
{
// URL doesn't contain the "id" parameter
trace("No id found.");
}
}
答案 1 :(得分:1)
用String.split()划分它们并征服:
var url:String = "http://www.xxx.zzz/myapp?arg1=vae&arg2=victus";
var params:String = url.substr(url.lastIndexOf("?") + 1);
if (params.length == url.length) return; //no params
for each (var pair:String in params.split("&"))
{
trace("Got parameter:");
var nameValue:Array = pair.split("=");
trace("name: " + nameValue[0] + ", value: " + nameValue[1]);
}
输出:
Got parameter: name: arg1, value: vae Got parameter: name: arg2, value: victus