Question

我有以下字符串：

[{names: {en: "US 30 - 5 Minute Level", es: "US 30 - 5 Minute Level"}, status: "A", displayed: "Y", start_time: "2011-05-20 00:00:00", start_time_xls: {en: "20th of May 2011  00:00 am", es: "20 May 2011 00:00 am"}, suspend_at: "2011-05-20 16:53:48", is_off: "Y", score_home: "", score_away: "", bids_status: "", period_id: "", curr_period_start_time: "", score_extra_info: "", settled: "N", ev_id: 2688484, ev_type_id: 10745, num_mkts: 5, venues: {en: "", es: ""}, disporder: 2040, ev_stream_available: false}]

我需要用引号括住所有变量名，这样就会验证为JSON。我正在做以下事情，但它也分开了日期。。

Regex.Replace(input, @"(\w+:)", "\"$0\":", RegexOptions.None);

Regex.Replace之后的输出：

[{"names" {"en" "US 30 - 5 Minute Level", "es" "US 30 - 5 Minute Level"}, "status" "A", "displayed" "Y", "start_time" "2011-05-20 "00""00"00", "start_time_xls" {"en" "20th of May 2011 "00"00 am", "es" "20 May 2011 "00"00 am"}, "suspend_at" "2011-05-20 "16""53"48", "is_off" "Y", "score_home" "", "score_away" "", "bids_status" "", "period_id" "", "curr_period_start_time" "", "score_extra_info" "", "settled" "N", "ev_id" 2688484, "ev_type_id" 10745, "num_mkts" 5, "venues" {"en" "", "es" ""}, "disporder" 2040, "ev_stream_available" false}]

如何更改此选项以忽略它们？此外，什么是一个良好的基于Web的资源，一劳永逸地到达正则表达式的底部？！

感谢。

Answer 1

尝试这种模式：

string pattern = @"\b([A-Za-z_]+)\b(?=:)";
string replace = "\"$0\"";
string result = Regex.Replace(input, pattern, replace);
Console.WriteLine(result);

[A-Za-z_]+匹配任何大写/小写字母和下划线字符一次或多次。如果没有JSON名称包含数字，则此方法正常。 \b元字符匹配单词边界，(?=:)匹配 - 但不捕获 - 冒号。您会注意到replace模式不包含冒号。

同样，这种模式可以起作用：@"\b([^\d\s]+)\b(?=:)"因为它匹配的不是数字或空格。

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The 30 Minute Regex Tutorial
Regular Expressions Info - 很好的资源，解释了不同的概念，突出了各种语言的正则表达式引擎之间的差异。
Expresso - 这是一款免费工具，您只需提供一封电子邮件即可注册。它还包括我上面链接的30分钟正则表达式教程。

这应该让你开始。如果你真的想深入了解，那么请查看两本好书：

Mastering Regular Expressions - 强烈推荐
Regular Expressions Cookbook

C＃Regex.Replace，Colon as Delimiter，忽略DateTime格式

1 个答案: