如何在DynamicJasper </string>中设置list <string>的值

时间:2011-05-20 10:39:58

标签: list field dynamic-jasper

我需要在报告中生成动态的列数。所以我设置了我的JasperPrint大量的Object:

Object[] obj = new Object[selectedUsers.size()];
//fill the massive
JasperPrint jp = DynamicJasperHelper.generateJasperPrint(dr, new ClassicLayoutManager(), new JRBeanArrayDataSource(obj));

我的obj是一个班级:

public class ResultsDTO {
    private String login;
    private Integer id;
    private List<String> list;
    private Object[] results;

    public Object[] getResults() {
        return results;
    }

    public void setResults(Object[] results) {
        this.results = results;
    }

    public ResultsDTO(){

    }

    public ResultsDTO(Integer id,String login) {
        super();
        this.login = login;
        this.id = id;
    }

    public ResultsDTO(String login, Integer id, List<String> list) {
        super();
        this.login = login;
        this.id = id;
        this.list = list;
    }

    public String getLogin() {
        return login;
    }

    public void setLogin(String login) {
        this.login = login;
    }

    public Integer getId() {
        return id;
    }

    public void setId(Integer id) {
        this.id = id;
    }

    public List<String> getList() {
        return list;
    }

    public void setList(List<String> list) {
        this.list = list;
    }

    public void addToList(String day_result){
        this.list.add(day_result);
    }
}

然后我尝试创建列:

FastReportBuilder firstReport = new FastReportBuilder();
List<AbstractColumn> column_list = new ArrayList<AbstractColumn>();

AbstractColumn columnId = getColumn("id", Integer.class,"№", 30, headerStyle, detailStyle);
AbstractColumn columnLogin = getColumn("login", String.class,"ФИО", 150, headerStyle, detailStyle);

for (int i = 0; i < header.size(); i++){
    AbstractColumn column = getColumn("results", Object.class, header.get(i), 80, headerStyle, detailStyle);
    column_list.add(column);
}

最终我有一个例外:

  

net.sf.jasperreports.engine.design.JRValidationException:报告   设计无效:      1.文本字段表达式不支持“java.lang.Object”类。

请帮忙!我不知道如何使用jasper和list或array

1 个答案:

答案 0 :(得分:1)

Jasper Reports不允许将Object作为其元素的有效类型。我必须是以下之一:

  • 字符串
  • Number(或其任何子类)
  • 日期
  • 布尔

您应该询问表单中的每个元素的类,并将适当的类传递给列构建器。