我想删除登录的当前用户,这就是我使用过滤器的原因。 但我收到一个错误:
类型'Subscription'缺少类型'Observable []>'中的以下属性:_isScalar,源,运算符,提升和另外6个。
这是代码:
@Select(UserPageState.get('collection')) users$: Observable<Array<Partial<User>>>;
async ngOnInit() {
const USER = this.creds.credentials['id'];
this.users$.subscribe(param => param.filter(x => x.id !== USER));
await this.store.dispatch(new UserPageList({ start: 1, length: this.pageSize })).toPromise();
}
HTML
<ag-grid-angular
style="width: 100%; height: 100%;"
[class]="(darkMode$ | async) ? 'ag-theme-balham-dark' : 'ag-theme-balham'"
[gridOptions]="gridOptions"
[rowData]="users$ | async"
[columnDefs]="columnDefs"
[frameworkComponents]="frameworkComponents"
(gridReady)="onGridReady($event)"
(firstDataRendered)="onFirstDataRendered($event)"
>
</ag-grid-angular>
答案 0 :(得分:0)
问题在下面的语句中,订阅一个observable返回一个Subscription实例,然后您再次将其分配给observable。
this.users$ = this.users$.subscribe(param => param.filter(x => x.id !== USER));
只需不再将其分配给可观察对象,它将解决此问题。
this.users$.subscribe(param => param.filter(x => x.id !== USER));