根据注释者的结果过滤查询集

时间:2020-03-12 23:36:14

标签: python django django-queryset

因此,我有一个称为post的模型,它的一个字段是用户模型的外键,而我有另一个称为subscriptions的模型,该模型有2个外键,一个是指用户,另一个是指另一个帐户,想要过滤帖子查询集以仅显示来自存在订阅对象的用户的帖子,用户在其中订阅了帖子的创建者。我的模型如下:

class post(models.Model):
    creator = models.ForeignKey(Account,blank=False,null=False,on_delete=models.CASCADE)
    ...

class subscriptions(models.Model):
    subscriber = models.ForeignKey(Account,blank=False,null=False,on_delete = models.CASCADE, related_name='subscriber')
    subscribed_to = models.ForeignKey(Account,blank=False,null=False,on_delete = models.CASCADE, related_name='subscribed_to')

我尝试在视图中执行此操作

posts = post.objects.filter(creator__in = request.user.subscribed_to)

但它什么也没返回

这是我的帐户模型:

class Account(AbstractBaseUser):
    email = models.EmailField(verbose_name='email', max_length=60, unique=True)
    username = models.CharField(max_length=30, unique=True)
    first_name = models.CharField(max_length=30)
    last_name = models.CharField(max_length=30)
    addresse = models.CharField(max_length=60)
    city = models.CharField(max_length=50)
    party_count = models.IntegerField(default=0)
    verified = models.BooleanField(default=False)
    profil_pic = models.ImageField(upload_to='profil_pics/',blank=True)
    birthday = models.DateField(default=date.today())
    date_joined = models.DateTimeField(verbose_name='date_joined', auto_now_add=True)
    last_login = models.DateTimeField(verbose_name='last_login', auto_now=True)
    is_admin = models.BooleanField(default=False)
    is_active = models.BooleanField(default=True)
    is_staff = models.BooleanField(default=False)
    is_superuser = models.BooleanField(default=False)

    USERNAME_FIELD = 'username'
    REQUIRED_FIELDS = ['email','first_name','last_name','addresse','birthday','city']

    objects = MyAccountManager()

    def __str__(self):
        return self.username

    def has_perm(self, perm, obj=None):
        return self.is_admin

    def has_module_perms(self,app_label):
        return True

2 个答案:

答案 0 :(得分:1)

您可以在一个查询中解决它。

Post.objects.filter(creator__subscribed_to__subscriber=request.user)

答案 1 :(得分:0)

做完一些研究后,我最终找到了一些导致以下情况的信息:

subs = subscriptions.objects.filter(subscriber=request.user).values_list('subscribed_to')
posts = post.objects.filter(creator__in = subs
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