Question

我正在使用ServiceTestCase为服务编写单元测试。

该服务基本上执行AsyncTask，它执行一些工作，然后在onPostExecute（）中执行其他操作。

当我在（虚拟）设备中运行和调试它时，服务按预期工作。

但是在扩展ServiceTestCase的测试中，我只进入了doInBackground（）。一旦方法返回，onPostExecute（）永远不会被调用。我让测试sleep（）所以AsyncTask有时间完成它的工作。

这是简化服务：

public class ServiceToTest extends Service {
    private AtomicBoolean busy = new AtomicBoolean(false);

    @Override
    public IBinder onBind(final Intent intent) {
        return null;
    }

    @Override
    public int onStartCommand(final Intent intent, final int flags,
        final int startId) {
        this.handleCommand();
        return START_NOT_STICKY;
    }

    /**
    * Workaround for http://code.google.com/p/android/issues/detail?id=12117
    */
    @Override
    public void onStart(final Intent intent, final int startId) {
        this.handleCommand();
    }

    public void handleCommand() {
        new TaskToTest().execute();
    }

    public boolean isBusy() {
        return busy.get();
    }

    private class TaskToTest extends AsyncTask<Boolean, Void, TestInfo> {
        @Override
        protected void onPreExecute() {
            busy.set(true);
        }

        @Override
        protected TestInfo doInBackground(final Boolean... args) {
            return null;
        }

        @Override
        protected void onPostExecute(final TestInfo info) {
            busy.set(false);
        }
    }
}

这是对它的测试：

public class ServiceTest extends ServiceTestCase<ServiceToTest> {
    public ServiceTest() {
        super(ServiceToTest.class);
    }

    public void testIsBusy() throws InterruptedException {
        startService(new Intent("this.is.the.ServiceToTest"));  
        ServiceToTest serviceToTest = this.getService();
        assertTrue(serviceToTest.isBusy());
        Thread.sleep(10000);
        assertFalse(serviceToTest.isBusy());
    }
}

我认为ServiceTestCase提供的环境有些限制，所以这不起作用，但是我能做些什么才能让它工作？

干杯，托

Answer 1

问题是你的后台线程正在等待用户界面“活着”，你需要拨打Looper.prepare()和Looper.loop()。最好在this page中解释。

Answer 2

所以只是跟进我如何使用dmon提供的信息。

我将测试改为以下内容：

public class ServiceTest extends ServiceTestCase {



public ServiceTest() {
    super(ServiceToTest.class);
}

public void testIsBusy() throws InterruptedException {

    // Starts the service and asserts that onPreExecute() was called
    ServiceTestThread serviceTestThread = new ServiceTestThread();
    serviceTestThread.start();

    // Wait for the service to start and complete doInBackground()
    // TODO Implement something smarter than this...
    Thread.sleep(1000);

    // Assert that onPostExecute() was called
    assertFalse(serviceTestThread.serviceToTest.isBusy());

}

private class ServiceTestThread extends Thread {

    ServiceToTest serviceToTest;

    public void run() {
        Looper.prepare();

        startService(new Intent("this.is.the.ServiceToTest"));

        serviceToTest = getService();

        assertTrue(serviceToTest.isBusy());

        Looper.loop();
    }

}

public ServiceTest() { super(ServiceToTest.class); } public void testIsBusy() throws InterruptedException { // Starts the service and asserts that onPreExecute() was called ServiceTestThread serviceTestThread = new ServiceTestThread(); serviceTestThread.start(); // Wait for the service to start and complete doInBackground() // TODO Implement something smarter than this... Thread.sleep(1000); // Assert that onPostExecute() was called assertFalse(serviceTestThread.serviceToTest.isBusy()); } private class ServiceTestThread extends Thread { ServiceToTest serviceToTest; public void run() { Looper.prepare(); startService(new Intent("this.is.the.ServiceToTest")); serviceToTest = getService(); assertTrue(serviceToTest.isBusy()); Looper.loop(); } }

我现在将看到使这个ServiceTestThread更通用，以便可以重复使用。

的Torsten

Answer 3

不确定这对其他人是否有用，但这是我尝试提取Tortens的答案并使其更具可重用性。

    private synchronized boolean getWaitFlag()
    {
        return _waitFlag;
    }

    private boolean _waitFlag;

    private synchronized void setWaitFlag(boolean value)
    {
        _waitFlag = value;
    }

    private void waitForCompletionFlag() throws InterruptedException
    {
        Calendar cal = Calendar.getInstance();
        while (getWaitFlag() == false)
        {
            Thread.sleep(10);
            if (Calendar.getInstance().getTimeInMillis() - cal.getTimeInMillis() > 1000) // Wait at most 1 second
            {
                Log.e("timeout", "timed out waiting to complete task");
                break;
            }
        }
    }

private abstract class EmulatedUI extends Thread
    {
        public abstract void doWork();

        public void run()
        {
            Looper.prepare();
            doWork();
            Looper.loop();
        }
    }

public void testSomething() throws InterruptedException
{
    EmulatedUI thread = new EmulatedUI() {

        @Override
        public void doWork()
        {
            _objectToTest.someAsyncCall(new WorkCompletedCallback() {

                        @Override
                        public void onComplete()
                        {
                                   // could possibly assert things here
                            setWaitFlag(true);
                        }
                    });

        }
    };
    thread.start();
    waitForCompletionFlag();
    // assert things here since you know the async task has completed.
}

Answer 4

尝试从测试运行程序线程而不是ui线程绑定到服务时遇到了同样的问题。尝试从ui线程调用startService。

public void testIsBusy() throws Exception {
  final CountDownLatch latch = new CountDownLatch(1);

  new Handler(Looper.getMainLooper()).post(new Runnable() {
    @Override
    public void run() {
      startService(new Intent("this.is.the.ServiceToTest"));  
      ServiceToTest serviceToTest = this.getService();
      assertTrue(serviceToTest.isBusy());
      Thread.sleep(10000);
      assertFalse(serviceToTest.isBusy());
      latch.countDown();
    }
  });

  latch.await(5, TimeUnit.SECONDS);
}

AsyncTask.onPostExecute（）永远不会在ServiceTestCase中调用

4 个答案: