Question

我使用具有自定义受保护路线的到达/路由器：

const ProtectedRoute = ({ component: Component, ...rest }) => (
  localStorage.getItem('user_id') ? <Component {...rest} /> : <Redirect from="" to="/login" noThrow />
);

const LoginRoute = ({ component: Component, ...rest }) => (
  localStorage.getItem('user_id') ? <Redirect from="" to="/home" noThrow /> : <Component {...rest} />
);

const PublicRoute = ({ component: Component, ...rest }) => (
  <Component {...rest} />
);

<Router>
  <LoginRoute component={Login} path="/login" />
  <PublicRoute default component={Notfound} />

  <ProtectedRoute component={landingPage} path="/home" />
  <ProtectedRoute path="/" component={App} />
  <ProtectedRoute component={UserList} path="user" />
  <ProtectedRoute component={UserDetail} path="user/create" />
</Router>

我希望将其与user/:id嵌套路由

<ProtectedRoute component={UserList} path="user" />
<ProtectedRoute component={UserDetail} path="user/create" />

我该怎么办？

Answer 1

我觉得你正在使事情复杂化


const Routes = () => {
  const [loggedIn, setLoggedIn] = useState(false)

  useEffect(() => {
    localStorage.getItem('user_id') && setLoggedIn(true)
  }, [])

return (
  <Router>
    <LoginRoute component={Login} path="/login" />
    <Notfound default />

    {
      loggedIn 
      ? (
        <>
         <LandingPage path="/home" />
         <App path="/" component={App} />
         <UserList component={UserList} path="user">
           <UserDetail component={UserDetail} path="create" />
         </UserList>
        </>
       ) : (
        <Redirect from="" to="/login" noThrow />
       )
      }
     </Router>
  )
}

万一这无法按预期工作或您想以自己的方式使用它，请


<Router>
  ...
  <ProtectedRoute component={UserList} path="user">
    <UserDetail path="create" />
  </ProtectedRoute>
</Router>

ProtectedRoute无需使用UserDetail HOC，因为它已经嵌套在ProtectedRoute下

，然后在UserList中使用props.children渲染UserDetail

@ reach / router嵌套受保护的路由

1 个答案: