ch = input("Enter any value: ")
if((ch>='a' and ch<='z') or (ch>='A' and ch<='Z')):
print(ch, "is an alphabet.")
elif(ch%2==0):
print("even")
else(ch%2=!0):
print("odd")
答案 0 :(得分:0)
检查值是否为数字的最好方法是尝试一下。
ch = input("Enter any value: ")
try:
v = int(ch)
except ValueError:
print(ch, "is not a number")
else:
if v % 2 == 0:
print("even")
else:
print("odd")