在异步闭包中获取对共享数据的引用

Question

我正在努力从try_for_each_concurrent调用的闭包中获取共享数据：

use futures::channel::oneshot;
use std::sync::Arc;

use futures::stream::{self, StreamExt, TryStreamExt};

fn main() {
    let arc_val = Arc::new(5);

    let (tx1, rx1) = oneshot::channel();
    let (tx2, rx2) = oneshot::channel();
    let (_tx3, rx3) = oneshot::channel();

    let stream = stream::iter(vec![rx1, rx2, rx3]);
    let future =
        stream
            .map(Ok)
            .try_for_each_concurrent(5, |channels: oneshot::Receiver<u32>| async move {
                let arc_ref = Arc::clone(&arc_val);
                use_arc(arc_ref).await
            });
}

async fn use_arc(arc_ref: Arc<u32>) -> Result<(), String> {
    println!("Value {}", arc_ref);
    Ok(())
}

（Playground）

错误：

error[E0507]: cannot move out of `arc_val`, a captured variable in an `FnMut` closure
  --> src/main.rs:17:87
   |
7  |       let arc_val = Arc::new(5);
   |           ------- captured outer variable
...
17 |               .try_for_each_concurrent(5, |channels: oneshot::Receiver<u32>| async move {
   |  _______________________________________________________________________________________^
18 | |                 let arc_ref = Arc::clone(&arc_val);
   | |                                           -------
   | |                                           |
   | |                                           move occurs because `arc_val` has type `std::sync::Arc<u32>`, which does not implement the `Copy` trait
   | |                                           move occurs due to use in generator
19 | |                 use_arc(arc_ref).await
20 | |             });
   | |_____________^ move out of `arc_val` occurs here

发生的错误是我实际遇到的错误的概括版本，但是解决该错误应该可以解决我的问题。