将管道输出直接传递到purrr贴图功能

时间:2020-03-09 14:05:41

标签: r tidyverse purrr

此问题与我之前的问题here一致。但是,我尝试将管道调用的输出与purrr的map函数组合到一个管道中。例如:

library(tidyverse)
library(purrr)

my_tbl <- tibble(a = rep(c(0, 1), each = 5),
             b = rep(c(0, 1), times = 5),
             c = runif(10),
             d = rexp(10)) %>%
    mutate_at(vars(1,2), as.factor)

map(names(my_tbl)[-1], ~glm(reformulate(.x, "a"), data = my_tbl, family = "binomial")) %>% summary()

我尝试过

my_tbl <- tibble(a = rep(c(0, 1), each = 5),
             b = rep(c(0, 1), times = 5),
             c = runif(10),
             d = rexp(10)) %>%
    mutate_at(vars(1,2), as.factor) %>%
    {map(names(.)[-1], ~glm(reformulate(.x, "a"), data = ., family = "binomial")) %>% summary()}

但是我得到了:

Error in eval(predvars, data, env) : 
  invalid 'envir' argument of type 'character'

1 个答案:

答案 0 :(得分:1)

在这种情况下,您不需要purrr:

custom_fun <- function(x) {
  glm(reformulate(names(x)[-1], "a"), data = x, family = "binomial") %>% 
    summary
}

my_tbl <- tibble(a = rep(c(0, 1), each = 5),
                 b = rep(c(0, 1), times = 5),
                 c = runif(10),
                 d = rexp(10)) %>%
  mutate_at(vars(1,2), as.factor) %>% 
  custom_fun()

您可以将purrr与以下内容配合使用:

my_tbl <- tibble(a = rep(c(0, 1), each = 5),
                 b = rep(c(0, 1), times = 5),
                 c = runif(10),
                 d = rexp(10)) %>%
  mutate_at(vars(1,2), as.factor) %>% 
  nest(data = everything()) %>% 
  mutate(res = map(data, custom_fun))
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