此问题与我之前的问题here一致。但是,我尝试将管道调用的输出与purrr
的map函数组合到一个管道中。例如:
library(tidyverse)
library(purrr)
my_tbl <- tibble(a = rep(c(0, 1), each = 5),
b = rep(c(0, 1), times = 5),
c = runif(10),
d = rexp(10)) %>%
mutate_at(vars(1,2), as.factor)
map(names(my_tbl)[-1], ~glm(reformulate(.x, "a"), data = my_tbl, family = "binomial")) %>% summary()
我尝试过
my_tbl <- tibble(a = rep(c(0, 1), each = 5),
b = rep(c(0, 1), times = 5),
c = runif(10),
d = rexp(10)) %>%
mutate_at(vars(1,2), as.factor) %>%
{map(names(.)[-1], ~glm(reformulate(.x, "a"), data = ., family = "binomial")) %>% summary()}
但是我得到了:
Error in eval(predvars, data, env) :
invalid 'envir' argument of type 'character'
答案 0 :(得分:1)
在这种情况下,您不需要purrr:
custom_fun <- function(x) {
glm(reformulate(names(x)[-1], "a"), data = x, family = "binomial") %>%
summary
}
my_tbl <- tibble(a = rep(c(0, 1), each = 5),
b = rep(c(0, 1), times = 5),
c = runif(10),
d = rexp(10)) %>%
mutate_at(vars(1,2), as.factor) %>%
custom_fun()
您可以将purrr与以下内容配合使用:
my_tbl <- tibble(a = rep(c(0, 1), each = 5),
b = rep(c(0, 1), times = 5),
c = runif(10),
d = rexp(10)) %>%
mutate_at(vars(1,2), as.factor) %>%
nest(data = everything()) %>%
mutate(res = map(data, custom_fun))