Question

我有这个代码从数据库中提取一些数据，

$this->db->select('job_id, jobs.employer_id, COUNT(company_job_id) AS views, COUNT(like_job_id) AS likes, logo, company_name')
        ->from('jobs')
        ->join('company_likes', 'company_likes.like_job_id = jobs.employer_id', 'left')
        ->join('company_views', 'company_views.company_job_id = jobs.employer_id', 'left')
        ->join('employers', 'employers.employer_id = jobs.employer_id', 'left')
        ->group_by('company_views.company_job_id');

        $query = $this->db->get();

        return $query->result_array();

我得到了一些奇怪的结果，下面是在company_likes表中有0条记录和公司视图表中有6条记录的结果转储的镜头，

    Array
(
    [0] => Array
        (
            [job_id] => 1
            [employer_id] => 1
            [views] => 6
            [likes] => 0
            [logo] => 11d4df5e2f7db152cd9bcc3782dd03b0.jpg
            [company_name] => Test Company
        )

)

但是，如果我在company_views表中有6条记录，而公司的1条记录就像表格，我会得到以下内容，

Array
(
    [0] => Array
        (
            [job_id] => 1
            [employer_id] => 1
            [views] => 6
            [likes] => 6
            [logo] => 11d4df5e2f7db152cd9bcc3782dd03b0.jpg
            [company_name] => Test Company
        )

)

就好像观点和喜欢正在成倍增加或者某种东西，我怎么能这样做才能真实再现数据库中的内容？

以下是相关数据和表格的导出

--
-- Table structure for table `company_likes`
--

CREATE TABLE IF NOT EXISTS `company_likes` (
  `like_id` int(10) NOT NULL AUTO_INCREMENT,
  `like_job_id` int(11) NOT NULL,
  PRIMARY KEY (`like_id`),
  KEY `fk_company_likes_jobs1` (`like_job_id`)
) ENGINE=InnoDB  DEFAULT CHARSET=latin1 AUTO_INCREMENT=2 ;

--
-- Dumping data for table `company_likes`
--

INSERT INTO `company_likes` (`like_id`, `like_job_id`) VALUES
(1, 1);

-- --------------------------------------------------------

--
-- Table structure for table `company_views`
--

CREATE TABLE IF NOT EXISTS `company_views` (
  `view_id` int(10) NOT NULL AUTO_INCREMENT,
  `company_job_id` int(11) NOT NULL,
  PRIMARY KEY (`view_id`),
  KEY `fk_company_views_jobs1` (`company_job_id`)
) ENGINE=InnoDB  DEFAULT CHARSET=latin1 AUTO_INCREMENT=7 ;

--
-- Dumping data for table `company_views`
--

INSERT INTO `company_views` (`view_id`, `company_job_id`) VALUES
(1, 1),
(2, 1),
(3, 1),
(4, 1),
(5, 1),
(6, 1);

-- --------------------------------------------------------

--
-- Table structure for table `employers`
--

CREATE TABLE IF NOT EXISTS `employers` (
  `employer_id` int(11) NOT NULL AUTO_INCREMENT,
  `company_name` varchar(80) NOT NULL,
  `company_summary` text NOT NULL,
  `logo` varchar(60) NOT NULL,
  `alternative_ads` varchar(100) DEFAULT NULL,
  `facebook_url` varchar(100) DEFAULT NULL,
  `twitter_url` varchar(100) DEFAULT NULL,
  `user_id` int(10) NOT NULL,
  PRIMARY KEY (`employer_id`),
  KEY `fk_employers_users` (`user_id`)
) ENGINE=InnoDB  DEFAULT CHARSET=latin1 AUTO_INCREMENT=3 ;

--
-- Dumping data for table `employers`
--

INSERT INTO `employers` (`employer_id`, `company_name`, `company_summary`, `logo`, `alternative_ads`, `facebook_url`, `twitter_url`, `user_id`) VALUES
(1, 'Test Company', 'Test company is excatly what it says it is a test company, we have created this test company so that we can see that moovjob is functioning as it should be and that everything is upload, saving, applying and generally saving as we would expect.', '11d4df5e2f7db152cd9bcc3782dd03b0.jpg', 'http://www.simonainley.info/alternative', 'http://www.facebook.com/simon.ainley', 'http://www.twitter.com/simonainley', 2),
(2, 'Test Company', 'Test company summary', '006474cf842654eb28deebec7e4dcbb9.png', 'http://www.simonainley.info/alternative', 'http://www.facebook.com/simon.ainley', 'http://www.twitter.com/simonainley', 5);

-- --------------------------------------------------------

--
-- Table structure for table `jobs`
--

CREATE TABLE IF NOT EXISTS `jobs` (
  `job_id` int(11) NOT NULL AUTO_INCREMENT,
  `job_title` varchar(80) NOT NULL,
  `sectors` varchar(255) NOT NULL,
  `salary` varchar(20) NOT NULL,
  `retrain` enum('yes','no') NOT NULL,
  `bonuses_available` enum('yes','no') NOT NULL,
  `bonus_description` text,
  `job_summary` text NOT NULL,
  `job_description` text NOT NULL,
  `employer_id` int(11) NOT NULL,
  PRIMARY KEY (`job_id`),
  KEY `fk_jobs_employers1` (`employer_id`)
) ENGINE=InnoDB  DEFAULT CHARSET=latin1 AUTO_INCREMENT=2 ;

--
-- Dumping data for table `jobs`
--

INSERT INTO `jobs` (`job_id`, `job_title`, `sectors`, `salary`, `retrain`, `bonuses_available`, `bonus_description`, `job_summary`, `job_description`, `employer_id`) VALUES
(1, 'Test Jobtitle', 'Sector 1', '&pound;25,000', 'no', 'yes', 'Bonus Description', 'Job Summary', 'Job Description', 1);

--
-- Constraints for dumped tables
--

--
-- Constraints for table `company_views`
--
ALTER TABLE `company_views`
  ADD CONSTRAINT `company_views_ibfk_1` FOREIGN KEY (`company_job_id`) REFERENCES `jobs` (`employer_id`) ON DELETE NO ACTION ON UPDATE NO ACTION;

--
-- Constraints for table `employers`
--
ALTER TABLE `employers`
  ADD CONSTRAINT `fk_employers_users` FOREIGN KEY (`user_id`) REFERENCES `users` (`user_id`) ON DELETE NO ACTION ON UPDATE NO ACTION;

--
-- Constraints for table `jobs`
--
ALTER TABLE `jobs`
  ADD CONSTRAINT `fk_jobs_employers1` FOREIGN KEY (`employer_id`) REFERENCES `employers` (`employer_id`) ON DELETE NO ACTION ON UPDATE NO ACTION;

Answer 1

你有没有想过打破查询？您可以创建一个组合部分查询的临时表，然后使用第二个查询完成初始查询的其他部分！

我不相信活动记录类有什么可以创建临时表的，所以你需要手工完成。

我还可以看到查询被分解成更小的块并使用php进行一些比较并为您计数。

否则，一些示例数据和表创建信息可能很有用，因此我们也可以尝试查询。

Mysql - Codeigniter主动记录帮助

1 个答案: