<?php
$title = $_POST['title'];
$date = $_POST['date'];
$time = $_POST['time'];
$channel = $_POST['channel'];
mysql_connect("localhost","root","");
mysql_select_db("imammuda");
$sql=mysql_query("insert into Program (ID, Title, Date, Time, Channel) values ('NULL', $title, $date, $time, $channel);
mysql_close();
?>
这是我插入数据的POST
private void adddataintophp(String title, String date, String time, String channel){
ArrayList<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>();
//http post
try{
nameValuePairs.add(new BasicNameValuePair("title", title));
nameValuePairs.add(new BasicNameValuePair("date", date));
nameValuePairs.add(new BasicNameValuePair("time", time));
nameValuePairs.add(new BasicNameValuePair("channel", channel));
HttpClient httpclient = new DefaultHttpClient();
HttpPost httppost = new HttpPost("http://10.0.2.2/insertprogram.php");
httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
HttpResponse response = httpclient.execute(httppost);
HttpEntity entity = response.getEntity();
is = entity.getContent();
}catch(Exception e){
Log.e("log_tag", "Error in http connection"+e.toString());
}
}
运行php时,它给了我
Parse error: syntax error, unexpected $end in C:\wamp\www\InsertProgram.php on line 10
我不知道为什么它不能结束。
请在POST那里帮助我,我觉得那里有一些我没有找到它的错误。
答案 0 :(得分:9)
使用)"
$sql=mysql_query("insert into Program (ID, Title, Date, Time, Channel) values ('NULL', $title, $date, $time, $channel)");
答案 1 :(得分:6)
关闭双引号并将列值放在单引号中
$sql=mysql_query("insert into Program (ID, Title, Date, Time, Channel)
values ('NULL', '$title','$date', '$time', '$channel'");
附注:在将用户输入发送到mysql服务器之前转义用户输入。
答案 2 :(得分:2)
$sql=mysql_query("insert into Program (ID, Title, Date, Time, Channel) values ('NULL', $title, $date, $time, $channel)");
你忘了结束语。
答案 3 :(得分:1)
mysql_query("insert into Program (ID, Title, Date, Time, Channel) values ('NULL', $title, $date, $time, $channel);
您没有结束SQL-String。添加“在字符串的末尾。