Question

我编写了一个调用RESTful Web服务的android类。如果请求成功，响应将是JSON对象。我写这样的android类：

public class android extends Activity {

    public void onCreate(Bundle savedInstanceState)
    {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.main);
    TextView txt = (TextView) findViewById(R.id.textView1);
    txt.setText(getInputStreamFromUrl("http://localhost:8080/kyaw"));
    }

    public static String getInputStreamFromUrl(String url) {
          InputStream content = null;
          try {
            HttpClient httpclient = new DefaultHttpClient();
            HttpResponse response = httpclient.execute(new HttpGet(url));
            content = response.getEntity().getContent();
          } catch (Exception e) {
            Log.e("[GET REQUEST]", "Network exception");
          }
            String result=convert(content);
            return result;
        }

    private static String convert(InputStream in)
    {
        BufferedReader reader=new BufferedReader(new InputStreamReader(in));
        StringBuilder sb=new StringBuilder();
        String line=null;
        try{
            while((line=reader.readLine())!=null){
                sb.append(line+"\n");
            }
        }catch(Exception e)
        {
            e.printStackTrace();
        }finally{
            try{
                in.close();
            }catch(IOException e){
                e.printStackTrace();
            }
        }
        return sb.toString();
    }

}

我运行后遇到问题。我会得到异常因为我返回一个字符串。但是响应是JSON。我应该如何将JSON转换为String或其他方式然后如何在android屏幕中显示结果？

感谢 enter image description here

Answer 1

我这样做：

HttpClient client = new DefaultHttpClient();
HttpPost poster = new HttpPost("http://www.example.com/json.php");
poster.addHeader("Content-Type", "text/json");
poster.setEntity(new StringEntity(data.toString()));
//data being a json object created and filled earlier
HttpResponse response = client.execute(poster);                                 
if(response.getStatusLine().getStatusCode() == HttpStatus.SC_OK)
{
    DataInputStream input = new DataInputStream(response.getEntity().getContent());
    JSONObject json = new JSONObject(input.readLine());
    json.toString(2);
}

Answer 2

好“http：// localhost：8080 / kyaw”是一个问题...由此你想到模拟器而不是模拟器的主机...并且你得到网络错误

尝试“http://ip.of.your.host:8080/kyaw”

编辑：

        content = response.getEntity().getContent();// here comes an error
      } catch (Exception e) {
        Log.e("[GET REQUEST]", "Network exception");//we catch it here
      }
      //here you got content == null
      //so you getting null point exception

如何将JSON响应转换为String并在屏幕中显示？

2 个答案: