我正在使用CQRS和MediatR库,试图学习一些最佳实践。 我遇到的一个问题是命令/查询处理程序中的代码重复。我想知道在处理程序之间共享逻辑的最佳方法是什么。
示例: 我有一个定义ID属性的抽象Entity类。所有实体都从该类继承。
public abstract class Entity
{
public long Id { get; private set; }
protected Entity(long id)
{
Id = id;
}
...
}
然后对于每个实体,我想创建一个GetById查询。这些查询之一如下所示:
public class GetUserByIdQuery : IRequest<UserDto>
{
public long UserId { get; set; }
public class Handler : IRequestHandler<GetUserByIdQuery, UserDto>
{
private readonly IRepository<User> repository;
private readonly IMapper mapper;
public Handler(IUnitOfWork unitOfWork, IMapper mapper)
{
repository = unitOfWork.GetRepository<User>();
this.mapper = mapper;
}
public async Task<UserDto> Handle(GetUserByIdQuery request, CancellationToken cancellationToken)
{
var user = await repository.FindAsync(request.UserId, null, cancellationToken);
if (user is null)
{
throw new EntityNotFoundException();
}
return mapper.Map<UserDto>(user);
}
}
}
问题是此类对于所有实体看起来都完全相同。没有CQRS,我可能会遇到这样的事情:
public class EntityFinder<TEntity, TDto> where TEntity : Entity
{
private readonly IRepository<TEntity> repository;
private readonly IMapper mapper;
public EntityFinder(IUnitOfWork unitOfWork, IMapper mapper)
{
repository = unitOfWork.GetRepository<TEntity>();
this.mapper = mapper;
}
public async Task<TDto> GetByIdAsync(long id)
{
var entity = await repository.FindAsync(id);
if (entity is null)
{
throw new EntityNotFoundException();
}
return mapper.Map<TDto>(entity);
}
}
我尝试对通用查询和处理程序执行类似的操作,但是MediatR找不到处理程序(即使尝试将其手动注册到DI容器时也是如此)。
避免这种重复的最佳方法是什么?
答案 0 :(得分:2)
您可以尝试以下代码吗?这样,您可以重用加载代码,同时提供一个端点来处理请求。
public class EntityFinder<TEntity, TDto> where TEntity : Entity
{ ... // Same as your code }
public class GetUserByIdQuery : IRequest<UserDto>
{
public long UserId { get; set; }
public class Handler : IRequestHandler<GetUserByIdQuery, UserDto>, EntityFinder<User, UserDto>
{
public Handler(IUnitOfWork unitOfWork, IMapper mapper) : base(unitOfWork, mapper)
{ }
public async Task<UserDto> Handle(GetUserByIdQuery request, CancellationToken cancellationToken)
=> await base.GetByIdAsync(request.UserId);
}
}