我想编写JPQL查询,以获取ID值为“多对多”表的行。我有两节课:
@Entity
@Table(name = "farm")
@Getter
public class Farm {
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
@Column(name = "id", nullable = false)
private Long id;
@Column(name = "name")
private String name;
@ManyToOne()
@NotFound(action = NotFoundAction.IGNORE)
@JoinColumn(name = "customer_id", referencedColumnName = "id")
private Customer customer;
@ManyToMany(cascade = CascadeType.ALL)
@JoinTable(name = "user_farm", joinColumns = @JoinColumn(name = "user_id"), inverseJoinColumns = @JoinColumn(name = "farm_id"))
private List<User> users = new ArrayList<>();
}
和
@Entity
@Table(name = "user")
@Getter
public class User {
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
@Column(name = "id", nullable = false)
private Long id;
@Column(name = "email")
private String email;
@Column(name = "password")
private String password;
@ManyToMany(mappedBy = "users")
private List<Farm> farms = new ArrayList<>();
@Column(name = "is_admin")
private Boolean isAdmin;
}
和一个存储库:
public interface FarmRepository extends JpaRepository<Farm, Long> {
@Query("select f from Farm f join f.users u where u.id=:userId")
List<Farm> findByUserId(@Param("userId") Long userId);
}
但是,我收到了这个休眠错误:
ERROR: column user2_.id does not exist
我如何正确编写jpql查询以使其起作用?
答案 0 :(得分:0)
该错误提示查询已执行,但您的数据库表不包含id列。
转到您的application.properties文件,并将其添加以在控制台中查看SQL:
spring.jpa.show-sql = true
spring.jpa.properties.hibernate.format_sql = true
执行测试,看看是否生成了正确的SQL。
考虑谁创建您的数据库?自动创建hbm2ddl模式?液基?飞路? schema.sql?修复数据库表。
答案 1 :(得分:0)
我想我可能也有类似的问题。表名“ user”通常是保留的,您不能使用它。尝试将其重命名为“ person”或其他名称。可能会有所帮助。
答案 2 :(得分:0)
据我所知,@ManyToMany
需要双向关系,但在您的示例中它是单向关系。让我们看一下结构:
User:
Long id;
Farm:
Long id;
User_farm:
Long r_user_id;
Long r_farm_id;
因此@JoinTable
必须是:
@ManyToMany(cascade = CascadeType.ALL)
@JoinTable(
name = "USER_FARM",
joinColumns = @JoinColumn(name = "r_user_id", referencedColumnName = "id"),
inverseJoinColumns = @JoinColumn(name = "r_farm_id", referencedColumnName = "id"))
private List<User> users;