我正在尝试遍历其值中包含多个行索引的字典,然后应用pd.nsmallest函数为该字典中的多组行索引生成前3个最小值。但是,我的for循环语句似乎出了点问题,因为我一遍又一遍地覆盖了前3个值,直到字典中的最后一组值为止,所以我的最终excel文件输出仅显示了最后一行的3行for循环。
当我使用print语句时,它可以按预期方式工作,并且我得到了字典中所有16个值的输出,但是当写入excel文件时,它只为我提供了循环中最后一次运行的输出
import pandas as pd
from tabulate import tabulate
VA = pd.read_excel('Columnar BU P&L.xlsx', sheet_name = 'Variance by Co')
legcon = VA[['Expense', 'Consolidation', 'Exp Category']]
legcon['Variance Type'] = ['Unfavorable' if x < 0 else 'favorable' for x in legcon['Consolidation']]
d = {'Travel & Entertainment': [1,2,3,4,5,6,7,8,9,10,11], 'Office supplies & Expenses': [13,14,15,16,17],
'Professional Fees':[19,20,21,22,23], 'Fees & Assessments':[25,26,27], 'IT Expenses':[29],
'Bad Debt Expense':[31],'Miscellaneous expenses': [33,34,35,36,37],'Marketing Expenses':[40,41,42],
'Payroll & Related Expenses': [45,46,47,48,49,50,51,52,53,54,55,56], 'Total Utilities':[59,60],
'Total Equipment Maint, & Rental Expense': [63,64,65,66,67,68],'Total Mill Expense':[70,71,72,73,74,75,76,77],
'Total Taxes':[80,81],'Total Insurance Expense':[83,84,85],'Incentive Compensation':[88],
'Strategic Initiative':[89]}
当我这样做时,直接输出打印效果很好
for key,value in d.items():
a = legcon.iloc[value][legcon.iloc[:,1]<0].nsmallest(3,'Consolidation')
print(a)
Expense Consolidation Exp Category Variance Type
5 Transportation - AIR -19054 Travel & Entertainment Unfavorable
9 Meals -9617 Travel & Entertainment Unfavorable
7 Lodging -9439 Travel & Entertainment Unfavorable
Expense Consolidation Exp Category Variance Type
26 Bank Charges -4320 Fees & Assessments Unfavorable
27 Finance Charges -1389 Fees & Assessments Unfavorable
25 Payroll Fees -1145 Fees & Assessments Unfavorable
但是,当我使用以下代码写入excel时:
writer = pd.ExcelWriter('testt.xlsx', engine = 'xlsxwriter')
row = 0
for key,value in d.items():
a = legcon.iloc[value][legcon.iloc[:,1]<0].nsmallest(3,'Consolidation')
for i in range(0,16):
a.to_excel(writer, sheet_name = 'test', startrow = row+4, index = False)
writer.save()
我非常感谢您提供有关如何更正此问题的反馈。提前致谢!
答案 0 :(得分:0)
在朋友的帮助下,我刚刚意识到我的愚蠢错误,我的for循环中没有行迭代器供输出在下一行输出,并使用以下代码解决了该问题(最初,我将行迭代器放置在其中我的df.to_excel语句):
writer = pd.ExcelWriter('testt.xlsx', engine = 'xlsxwriter')
row = 0
for key,value in d.items():
a = legcon.iloc[value][legcon.iloc[:,1]<0].nsmallest(3,'Consolidation')
a.to_excel(writer, sheet_name = 'Testt', startrow = row, index = False)
row = row+4
writer.save()