所以首先是这里的代码。随机声明位于第3行,随机用法位于第15行左右。
public static void wildPokemonEncounter(string pokemonRegion)
{
Pokemon wildPokemonEncountered = null;
Random rnd = new Random();
int possiblePokemon = 0;
foreach (KeyValuePair<string, pokemonStats> kvp in GameReference.pokemonInformation)
{
if (kvp.Key != "Bublbasuar" && kvp.Key != "Squirtle" && kvp.Key != "Charmander")
{
if (pokemonRegion == "Plain")
{
if ((kvp.Value.typeOfPokemon == "Plant" || kvp.Value.typeOfPokemon == "Normal" || kvp.Value.typeOfPokemon == "Bug") && kvp.Value.evolutionNumber==1)
{
possiblePokemon += 1;
}
}
}
}
int whichPokemon = rnd.Next(1, possiblePokemon);
int i = 1;
Console.WriteLine(possiblePokemon+" "+ i + " " + whichPokemon);
foreach (KeyValuePair<string, pokemonStats> kvp in GameReference.pokemonInformation)
{
if (kvp.Key != "Bulbasuar" && kvp.Key != "Squirtle" && kvp.Key != "Charmander")
{
if (pokemonRegion == "Plain")
{
pokemonStats thisPokemonsStats = GameReference.pokemonInformation[kvp.Key];
if ((thisPokemonsStats.typeOfPokemon == "Plant" || thisPokemonsStats.typeOfPokemon == "Normal" || thisPokemonsStats.typeOfPokemon == "Bug") && thisPokemonsStats.evolutionNumber == 1)
{
if (i == whichPokemon)
{
wildPokemonEncountered = new Pokemon(kvp.Key, kvp.Value);
slowTyper("`");
slowTyper("You found a Pokemon! Its a " + wildPokemonEncountered.name + "! Its level " + wildPokemonEncountered.level + " and of the type " + wildPokemonEncountered.typeOfPokemon + ".~");
Battle B = new Battle();
slowTyper("You enter into battle with the opposing Pokemon.");
Pokemon your_active_pokemon = null;
foreach (Pokemon pok in GameReference.pokemonInBag)
{
if (pok.is_Starting_Pokemon == true)
{
your_active_pokemon = pok;
}
}
B.PokemonBattle(wildPokemonEncountered, your_active_pokemon);
break;
}
else
{
i += 1;
}
}
}
}
}
}
我已经测试过只放入一会儿true循环,以检查由于某种原因随机变量在此代码区域中是否不起作用,但它是否起作用。但是由于某种原因,我每次运行它时,都会得到四个导致Rattata生成的信息。有什么想法吗?
答案 0 :(得分:2)
有多个stackoverflow源,其中提到创建new Random()
时间太近会导致几乎相同的种子(我无法从文档中对此进行验证)
Random number generator only generating one random number
其他人则说,如果过了毫秒,您就可以了:How much does new Random() depends on time?
实际上,我能想到的唯一可以解决您的问题的方法就是确实使用静态的Random变量,如下所示:
private static Random rnd = new Random();
public static void wildPokemonEncounter(string pokemonRegion)
{
Pokemon wildPokemonEncountered = null;
int possiblePokemon = 0;
foreach (KeyValuePair<string, pokemonStats> kvp in GameReference.pokemonInformation)
{
if (kvp.Key != "Bublbasuar" && kvp.Key != "Squirtle" && kvp.Key != "Charmander")
{
if (pokemonRegion == "Plain")
{
if ((kvp.Value.typeOfPokemon == "Plant" || kvp.Value.typeOfPokemon == "Normal" || kvp.Value.typeOfPokemon == "Bug") && kvp.Value.evolutionNumber==1)
{
possiblePokemon += 1;
}
}
}
}
int whichPokemon = rnd.Next(1, possiblePokemon);
int i = 1;
Console.WriteLine(possiblePokemon+" "+ i + " " + whichPokemon);
foreach (KeyValuePair<string, pokemonStats> kvp in GameReference.pokemonInformation)
{
if (kvp.Key != "Bulbasuar" && kvp.Key != "Squirtle" && kvp.Key != "Charmander")
{
if (pokemonRegion == "Plain")
{
pokemonStats thisPokemonsStats = GameReference.pokemonInformation[kvp.Key];
if ((thisPokemonsStats.typeOfPokemon == "Plant" || thisPokemonsStats.typeOfPokemon == "Normal" || thisPokemonsStats.typeOfPokemon == "Bug") && thisPokemonsStats.evolutionNumber == 1)
{
if (i == whichPokemon)
{
wildPokemonEncountered = new Pokemon(kvp.Key, kvp.Value);
slowTyper("`");
slowTyper("You found a Pokemon! Its a " + wildPokemonEncountered.name + "! Its level " + wildPokemonEncountered.level + " and of the type " + wildPokemonEncountered.typeOfPokemon + ".~");
Battle B = new Battle();
slowTyper("You enter into battle with the opposing Pokemon.");
Pokemon your_active_pokemon = null;
foreach (Pokemon pok in GameReference.pokemonInBag)
{
if (pok.is_Starting_Pokemon == true)
{
your_active_pokemon = pok;
}
}
B.PokemonBattle(wildPokemonEncountered, your_active_pokemon);
break;
}
else
{
i += 1;
}
}
}
}
}
}
希望有人可以验证一个或另一个,并为您解释相同的值。
using System;
using System.Collections.Generic;
public class Program
{
private static HashSet<int> randomValues = new HashSet<int>();
public static void Main()
{
for(int i = 0; i < 2000; i++)
{
wildPokemonEncounter();
}
Console.WriteLine("1st iteration results");
foreach(int rnd in randomValues) {
Console.WriteLine(rnd);
}
randomValues.Clear();
for(int i = 0; i < 20000; i++)
{
wildPokemonEncounter();
}
Console.WriteLine("2nd iteration results");
foreach(int rnd in randomValues) {
Console.WriteLine(rnd);
}
}
//static Random rnd = new Random();
public static void wildPokemonEncounter()
{
int possiblePokemon = 4;
Random rnd = new Random();
int whichPokemon = rnd.Next(1, possiblePokemon);
if(!randomValues.Contains(whichPokemon)) {
randomValues.Add(whichPokemon);
}
}
}
结果:
第一次迭代结果 3 第二次迭代结果 3 1个 2
它是如此之快以至于所有迭代都在1毫秒内完成。