我的Spring Batch上下文出了什么问题?

时间:2011-05-18 19:37:52

标签: java xml spring xsd spring-batch

以下是Spring Batch的上下文:

<beans:beans xmlns:beans="http://www.springframework.org/schema/beans"
  xmlns:b="http://www.springframework.org/schema/batch"
  xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
  xsi:schemaLocation="
    http://www.springframework.org/schema/beans
    http://www.springframework.org/schema/beans/spring-beans-2.5.xsd
    http://www.springframework.org/schema/batch
    http://www.springframework.org/schema/batch/spring-batch-2.1.xsd">
  <b:job id="bar" job-repository="my-job-repository">
    <b:step id="foo">
      <b:tasklet transaction-manager="my-transaction-manager">
        <b:chunk reader="itemReader" writer="itemWriter"/>
      <b:tasklet>
    </b:step>
  </b:job>
</beans:beans>

这就是Spring Batch所说的:

org.xml.sax.SAXParseException: cvc-complex-type.2.4.a: Invalid content was found
starting with element 'b:tasklet'. One of
'{"http://www.springframework.org/schema/batch":transaction-attributes,
"http://www.springframework.org/schema/batch":no-rollback-exception-classes,
"http://www.springframework.org/schema/batch":listeners,
"http://www.springframework.org/schema/beans":bean,
"http://www.springframework.org/schema/beans":ref}' is expected.

我的XML出了什么问题?

PS。我正在使用org.springframework.batch:spring-batch-core:2.1.7.RELEASE

1 个答案:

答案 0 :(得分:9)

您忘记关闭tasklet标记了。可能是从here复制并复制了错误