Question

我需要一些PHP的帮助。只是一点点解释：（我试图使用此代码显示5个结果

    $n_id = mysql_real_escape_string ($_GET['id']);
    $path = '';

    if(isset($n_id) && $n_id != "") {
        $sql = 'SELECT * FROM test2 WHERE id="' . $n_id . '"';
        $news = mysql_query($sql);

    if($result = mysql_fetch_array($news)) {
        $title = mysql_result($news,0,"title");
        $date = mysql_result($news,0,"date");
        echo '<b>' . $title . ' | ' . $date . '</b>
        <br/>
        <img src="images.php?id='. $n_id .'>';
    } else {
        header("Location: vendi.php");
    }
    echo '<br /><a href="/'.$path.'">Back to Archive</a>';
    }

显示但是想要第1个结果（图像+新闻的标题和其他结果只是标题）。希望我能清楚地写出我需要帮助的内容。谢谢

Answer 1

您的SQL语句仅提取一行。这不是一个完整的解决方案，但应该让你更接近：

if (isset($_GET['id']) && is_numeric($_GET['id'])) {
    $n_id = (int)$_GET['id'];
    $path = '';

    $count = 0;

    $sql = 'SELECT * FROM test2 WHERE id BETWEEN ' . $n_id ' AND ' . ($n_id + 5);
    $news = mysql_query($sql);

    while ($result = mysql_fetch_array($news)) {
        $title = $result['title'];
        $date = $result['date'];
        echo '<b>' . $title . ' | ' . $date . '</b>';
        if ($count < 1) {
            echo '<br/><img src="images.php?id='. $n_id .'>';
            $count++;
        }
    }

    if ($count == 0) { header("Location: vendi.php"); }

    echo '<br /><a href="/'.$path.'">Back to Archive</a>';
}

Answer 2

在循环搜索结果时，您可以检查您是否处于第一个结果：

$counter = 0;
while ($row = mysql_fetch_array($news)) {
    $title = mysql_result($news,0,"title");
    $date = mysql_result($news,0,"date");
    echo '<b>' . $title . ' | ' . $date . '</b>';
    if ( $counter == 0 ) {
        echo '<br /><img src="images.php?id='. $n_id .'>';
    }

}

Answer 3

这应该这样做。

$n_id = mysql_real_escape_string ($_GET['id']);
    $path = '';

    if(isset($n_id) && $n_id != "") {
        $sql = 'SELECT * FROM test2 WHERE id="' . $n_id . '"';
        $news = mysql_query($sql);

        $first = TRUE;
        if($result = mysql_fetch_array($news)) {
            $title = mysql_result($news,0,"title");
            $date = mysql_result($news,0,"date");

            if($first == TRUE) {
                echo '<b>' . $title . ' | ' . $date . '</b>';
                $first = FALSE;
            }
            else {
                echo '<b>' . $title . ' | ' . $date . '</b>
                <br/>
                <img src="images.php?id='. $n_id .'>';
            }
        }
        else {
            header("Location: vendi.php");
        }
        echo '<br /><a href="/'.$path.'">Back to Archive</a>';
        }
    }

显示PHP结果？

3 个答案: