Question

我正试图显示一个用于调试目的的蚂蚁模式集。在我的示例中，patternset显示为dontcompile patternSet {包括：[]排除：[]}，没有显示excludes文件中的信息。

我知道excludesfile可以正常工作，因为在Linux上最后没有显示Windows源。

build.xml

<project default="init" >

    <condition property="osname" value="linux">
        <os family="unix" />
    </condition>
    <!-- if it's not unix assume it's some kind of windows -->
    <property name="osname" value="windows" />

    <target name="init" >

        <local name="dont_compile.os.present" />
        <local name="dont_compile.present" />
        <available file="dont_compile.${osname}.lst" property="dont_compile.os.present" />
        <available file="dont_compile.lst" property="dont_compile.present" />

        <echo>dont_compile.${osname}.lst ${dont_compile.os.present}${line.separator}dont_compile.lst ${dont_compile.present}</echo>
        <patternset id="dontcompile">
            <excludesfile name="dont_compile.${osname}.lst" if="dont_compile.os.present" />
            <excludesfile name="dont_compile.lst" if="dont_compile.present" />
        </patternset>

        <fileset id="myfileset" dir=".">
            <include name="**/*.source" />
            <patternset refid="dontcompile" />
        </fileset>

<loadfile property="os_contents" srcFile="dont_compile.${osname}.lst" />
        <local name="ps.value" />
        <property name="ps.value" refid="dontcompile" />

        <echo>
dontcompile ${ps.value}"
os_contents ${os_contents}
${toString:myfileset}
</echo>
    </target>

</project>

dont_compile.linux.lst的内容

windows.source
win/**

我的测试目录的内容

./build.xml
./dont_compile.linux.lst
./general.source
./linux.source
./windows.source
./win/sub.source

样本输出

Buildfile: build.xml

init:
     [echo] dont_compile.linux.lst true
     [echo] dont_compile.lst ${dont_compile.present}
     [echo]
     [echo] dontcompile patternSet{ includes: [] excludes: [] }"
     [echo] os_contents windows.source
     [echo] win/sub.source
     [echo]
     [echo] general.source;linux.source

BUILD SUCCESSFUL
Total time: 0 seconds

如何显示蚂蚁模式集

0 个答案: