在会议室数据库中插入值

时间:2020-02-29 11:48:59

标签: android android-room

我正在尝试使用以下按钮单击将数据插入数据库:

在我的 MainActivity 中,我正在使用:

 package com.example.trial;

 public CityViewModel  mcityViewModel;

  @Override
  protected void onCreate(Bundle savedInstanceState) {
 ImageButton fab = findViewById(R.id.fab);
    fab.setOnClickListener(new View.OnClickListener() {
      @Override
      public void onClick(View view) {
        String cityName = cityNameWeakReference.getText().toString();
        City cityItem = new City(cityName, 5.0,4.0);
        Snackbar.make(view, cityName+cityItem, Snackbar.LENGTH_LONG)
            .setAction("Action", null).show();
        mcityViewModel.insert(cityItem);
      }
    });

为了便于查看与数据库相关的代码,我已经在com.example.trial.db中定义了所有与数据库相关的文件(除了DbActivity中显示了recyclerview的文件)。

我的实体

package com.example.trial.db

Entity(tableName = "city_table")
public class City {

  @NonNull
  @PrimaryKey
  @ColumnInfo(name = "city")
  private String city = "Atlantis";

  @NonNull
  @ColumnInfo(name = "latitude")
  private Double latitude = 0.0;

  @NonNull
  @ColumnInfo(name = "Longitude")
  private Double longitude = 0.0;

  public City(@NonNull String city, @NonNull Double latitude, @NonNull Double longitude) {
    this.city = city;
    this.latitude = latitude;
    this.longitude = longitude;
  }

  ... getter and setter for city, latitude and longitude ...
  ... not showing for brevity. If you think that is necessary, please ask...

package com.example.trial.db

@Dao
public interface CityDao{

  @Insert(onConflict = OnConflictStrategy.IGNORE)
  void insert(City city);

  @Query("DELETE FROM city_table")
  void deleteAll();

  @Delete
  void deleteCity(City city);

  @Query("SELECT * from city_table LIMIT 1")
  City[] getAnyCity();

  @Query("SELECT * from city_table ORDER BY city ASC")
  LiveData<List<City>> getAllCity();
}

ViewModel

package com.example.trial.db

public class CityViewModel extends AndroidViewModel {
    private CityRepository mRepository;
    private LiveData<List<City>> mAllCity;

    public CityViewModel(Application application) {
        super(application);
        mRepository = new CityRepository(application);
        mAllCity = mRepository.getAllCity();
    }

    public LiveData<List<City>> getAllCity() {
        return mAllCity;
    }

    public void insert(City city) { mRepository.insert(city); }
    public void deleteCity(City city) { mRepository.deleteCity(city); }
    public void deleteAll() {
        mRepository.deleteAll();
    }

}

现在,当我运行代码时,我得到了一个错误

java.lang.NullPointerException: Attempt to invoke virtual method 'void com.example.trial.db.CityViewModel.insert(com.example.trial.db.City)' on a null object reference

snackbar给出了一些值,这表明cityItem也不为空,但是仍然出现此错误。

我对Java很陌生,并尝试从this codelabs构建它。但是我无法在这里找出我在做什么错。

请帮助。

1 个答案:

答案 0 :(得分:1)

您似乎没有在mcityViewModel中初始化onCreate(Bundle savedInstanceState)

请在onCreate方法中添加以下行:

mcityViewModel = new ViewModelProvider(this).get(CityViewModel.class);

@Override
protected void onCreate(Bundle savedInstanceState) {
    // -------> Add this line here <-------
    mcityViewModel = new ViewModelProvider(this).get(CityViewModel.class);

    ImageButton fab = findViewById(R.id.fab);
    fab.setOnClickListener(new View.OnClickListener() {
      @Override
      public void onClick(View view) {
        String cityName = cityNameWeakReference.getText().toString();
        City cityItem = new City(cityName, 5.0,4.0);
        Snackbar.make(view, cityName+cityItem, Snackbar.LENGTH_LONG)
            .setAction("Action", null).show();
        mcityViewModel.insert(cityItem);
      }
    });
}