Question

我有一个数据帧，其中包含根据四列（SFDC_ID和left_side和right_SFDC_ID和right_side和相似性）重复的值：

现在，SFDC_ID和right_SFDC_ID正在通过以下方式复制：

SFDC_ID left_side   right_SFDC_ID   right_side  similairity

0013s00000vEVuwAAG  Hague Quality Water 0013s00000vEW72AAG  Hague Quality Waters    0.99023304
0013s00000vEW72AAG  Hague Quality Waters    0013s00000vEVuwAAG  Hague Quality Water 0.99023304

仔细观察，第1行的SFDC_ID与第2行的right_SFDC_ID相同。

我如何使用熊猫丢弃第二行？

Answer 1

这是一种方法：

# compares which is greater based on alphabetical order and makes a bool series
mask = df['SFDC_ID'] < df['right_SFDC_ID'] 

# creates a new column checking True vs False, 

#if mask is true item in df['SFDC_ID'] is selected else item in df['right_SFDC_ID'] is selected

df['col1'] = df['SFDC_ID'].where(mask, df['right_SFDC_ID'])

#same as above but a column for df['right_SFDC_ID']
df['col2'] = df['right_SFDC_ID'].where(mask, df['SFDC_ID'])

# checks for duplicates in `col1` and `col2` and removes last duplicate
df = df.drop_duplicates(subset=['col1', 'col2'])

Answer 2

您可以遍历行并删除与前几行值匹配的行

for index,row in df[1::].iterrows():
    prev_SFDC_ID = df.iloc[index-1]['SFDC_ID'] #get prev SFDC_ID value
    if row['right_SFDC_ID'] == prev_SFDC_ID: 
        df.drop(index=index, inplace=True)

基于两列删除重复行

2 个答案: