Question

我在下面有一张桌子。每天将运行3个不同的文件，状态将作为成功/失败插入到表中。我需要状态成功的所有3个文件并获取该日期。如下表所示，SQL查询必须返回Date 2020-02-25（因为所有3个文件都成功）

请帮助我进行查询，我尝试了很多查询，但无法获得所需的结果。

ID  Pipeline_name   Status      UpdatedDate
1   Student_Dump    SUCCESS     2020-02-27
2   Teacher_Dump    SUCCESS     2020-02-27
3   Subjects_Dump   Failed      2020-02-27  
4   Student_Dump    SUCCESS     2020-02-26
5   Teacher_Dump    Failed      2020-02-26
6   Subjects_Dump   SUCCESS     2020-02-26  
7   Student_Dump    SUCCESS     2020-02-25
8   Teacher_Dump    SUCCESS     2020-02-25
9   Subjects_Dump   SUCCESS     2020-02-25

Answer 1

尝试这个：

WITH cteStatus AS(
  SELECT UpdatedDate, Status, ROW_NUMBER() OVER (PARTITION BY UpdatedDate, Status ORDER BY UpdatedDate, Status) rn
    FROM T1
 )
SELECT c.UpdatedDate
  FROM cteStatus c
  WHERE Status = N'SUCCESS'
    AND rn = 3

想法是获取所有日期，其中每个日期都有“状态成功”的三个记录。

这里是Fiddle的链接：http://sqlfiddle.com/#!18/a25c2b/5/1

Answer 2

Demo on db<>fiddle

您可以使用Rownumber()来实现

Select ID,Pipeline_name,Status,UpdatedDate
from
(
  select *,row_number() over(partition by Status,UpdatedDate order by id) as rn
  from #table1
)A where rn=3 and Status = 'SUCCESS'

已更新

如果仅需要最新数据日期，则可以选择TOP 1与ORDER BY ID DESC组合

Select TOP 1 ID,Pipeline_name,Status,UpdatedDate
from
(
  select *,row_number() over(partition by Status,UpdatedDate order by id) as rn
  from #table1
)A where rn=3 and Status = 'SUCCESS'
ORDER BY ID DESC

Output here

Answer 3

您可以使用row_number()

Select * from
(
  select *,row_number() over(parition by updatedate,pipeline_name order by id) as rn
  from tablename
  where status='SUCCESS'
)A where rn=1

Answer 4

您可以进行聚合：

select UpdatedDate
from table t
group by UpdatedDate
having sum(case when statue = 'failed' then 1 else 0 end) = 0 and
       count(distinct Pipeline_name) = 3;

Answer 5

尝试一下：

select UpdatedDate from test where UpdatedDate not in 
(select UpdatedDate from test where status='Failed');

SQL查询以获取具有成功状态的记录

5 个答案: