嗨,我是php的新手,我正在使用php和phpmyadmin作为服务器来创建预订系统数据库和网站。我需要数据库编码方面的帮助。
具体地说,我正在尝试获取已登录用户的ID。
这是我的代码
// connect to database
$db = mysqli_connect('localhost', '#', '#', '#'); // hidden for security
// variable declaration
$username = "";
$email = "";
$errors = array();
// call the register() function if register_btn is clicked
if (isset($_POST['register_btn'])) {
register();
}
// call the login() function if register_btn is clicked
if (isset($_POST['login_btn'])) {
login();
}
if (isset($_GET['logout'])) {
session_destroy();
unset($_SESSION['user']);
header("location: login.php");
}
if (isset($_POST['pickup_date'])) {
book();
}
// REGISTER USER
function register(){
global $db, $errors;
// receive all input values from the form
$firstname = e($_POST['firstname']);
$surname = e($_POST['surname']);
$address = e($_POST['address']);
$home_postcode = e($_POST['home_postcode']);
$age = e($_POST['age']);
$email = e($_POST['email']);
$username = e($_POST['username']);
$password_1 = e($_POST['password_1']);
$password_2 = e($_POST['password_2']);
// form validation: ensure that the form is correctly filled
if (empty($firstname)) {
array_push($errors, "first name is required");
}
if (empty($surname)) {
array_push($errors, "surname is required");
}
if (empty($address)) {
array_push($errors, "address is required");
}
if (empty($home_postcode)) {
array_push($errors, "home postcode is required");
}
if (empty($age)) {
array_push($errors, "age is required");
}
if (empty($email)) {
array_push($errors, "Email is required");
}
if (empty($username)) {
array_push($errors, "Username is required");
}
if (empty($password_1)) {
array_push($errors, "Password is required");
}
if ($password_1 != $password_2) {
array_push($errors, "The two passwords do not match");
}
$password = $password_1;
// register user if there are no errors in the form
if (count($errors) == 0) {
if (isset($_POST['user_type'])) {
$user_type = e($_POST['user_type']);
$query = "INSERT INTO users (firstname, surname, address, home_postcode, age, email, username, user_type, password)
VALUES('$firstname', '$surname', '$address', '$home_postcode','$age','$email', '$username', '$user_type', '$password')";
mysqli_query($db, $query);
$_SESSION['success'] = "New user successfully created.";
header('location: home.php');
}else{
$query = "INSERT INTO users (firstname, surname, address, home_postcode, age, email, username, user_type, password)
VALUES('$firstname', '$surname', '$address', '$home_postcode','$age','$email', '$username', 'user', '$password')";
mysqli_query($db, $query);
// get id of the created user
$logged_in_user_id = mysqli_insert_id($db);
$_SESSION['user'] = getUserById($logged_in_user_id); // put logged in user in session
$_SESSION['success'] = "You are now logged in";
header('location: index.php');
}
}
}
// BOOK A CAR
function book() {
global $db, $errors;
// receive all input values from the form
$car_chosen = e($_POST['car_chosen']);
$pickup_date = e($_POST['pickup_date']);
$pickup_time = e($_POST['pickup_time']);
$return_date = e($_POST['return_date']);
$return_time = e($_POST['return_time']);
$collection_postcode = e($_POST['collection_postcode']);
// form validation: ensure that the form is correctly filled
if (empty($pickup_date)) {
array_push($errors, "pickup date is required");
}
if (empty($pickup_time)) {
array_push($errors, "pickup time is required");
}
if (empty($return_date)) {
array_push($errors, "return date is required");
}
if (empty($return_time)) {
array_push($errors, "return time is required");
}
if (empty($collection_postcode)) {
array_push($errors, "collection postcode is required");
}
// convert car chosen to the ID of that car
$query = "SELECT * FROM cars WHERE car_ID = " . $car_chosen;
// book car if there are no errors in the form
if (count($errors) == 0) {
$query = "INSERT INTO booking_details (pickup_date, pickup_time, return_date, return_time, total_cost, collection_postcode, car_fk, user_fk)
VALUES('$pickup_date', '$pickup_time', '$return_date', '$return_time', '1000', '$collection_postcode','$car_chosen','$id')";
if(mysqli_query($db, $query)){
echo 'hello';
}else{
echo "<br>" . $query . "<br>";
echo mysqli_error($db);
}
}
}
// return user array from their id
function getUserById($id){
global $db;
$query = "SELECT * FROM users WHERE user_id=" . $id;
$result = mysqli_query($db, $query);
$user = mysqli_fetch_assoc($result);
return $user;
}
// LOGIN USER
function login(){
global $db, $username, $errors;
// grab form values
$username = e($_POST['username']);
$password = e($_POST['password']);
// make sure form is filled properly
if (empty($username)) {
array_push($errors, "Username is required");
}
if (empty($password)) {
array_push($errors, "Password is required");
}
// attempt login if no errors on form
if (count($errors) == 0) {
$query = "SELECT * FROM users WHERE username='$username' AND password='$password'";
$results = mysqli_query($db, $query);
if (mysqli_num_rows($results) == 1) { // user found
// check if user is admin or user
$logged_in_user = mysqli_fetch_assoc($results);
if ($logged_in_user['user_type'] == 'admin') {
$_SESSION['user'] = $logged_in_user;
$_SESSION['success'] = "You are now logged in";
header('location: home.php');
}else{
$_SESSION['user'] = $logged_in_user;
$_SESSION['success'] = "You are now logged in";
header('location: index.php');
}
}else {
array_push($errors, "Wrong username/password combination");
}
}
}
function isLoggedIn()
{
if (isset($_SESSION['user'])) {
return true;
}else{
return false;
}
}
function isAdmin()
{
if (isset($_SESSION['user']) && $_SESSION['user']['user_type'] == 'admin' ) {
return true;
}else{
return false;
}
}
// escape string
function e($val){
global $db;
return mysqli_real_escape_string($db, trim($val));
}
function display_error() {
global $errors;
if (count($errors) > 0){
echo '<div class="error">';
foreach ($errors as $error){
echo $error .'<br>';
}
echo '</div>';
}
}
因此,我需要在他们登录后收集用户ID。我还需要它在首次注册后可以在用户登录的地方使用。
我不知道如何获得它,我只设法获得了所选汽车的ID。收集到user_id之后,我应该可以将其与其余值一起插入booking_details表中。
其他一切都正常。
感谢所有帮助。
答案 0 :(得分:0)
您应该从会话中获取用户详细信息
$user = $_SESSION['user'];
$loggeduserid = $user['id'];
注意:此处id是用户表的列名
答案 1 :(得分:-1)
您要将整行数据(数组)转储到$session['user']
$logged_in_user = mysqli_fetch_assoc($results);
$_SESSION['user'] = $logged_in_user;
因此,您应该仅能够使用ID列名称获取登录用户的ID。
$loggedInUserId = $_SESSION['user']['name_of_id_column'];
最后,我应该说清楚。您没有以安全的方式使用SQL。正如评论者所建议的那样,请研究PDO和准备好的声明。这比您想像的要容易。 https://phpdelusions.net/pdo