我想使用sql或python获取当年六月的第一个星期二。
例如:
答案 0 :(得分:2)
这是python方式。
import datetime
def get_day(year):
d = datetime.datetime(year, 6, 1)
offset = 1-d.weekday() #weekday = 1 means tuesday
if offset < 0:
offset+=7
return d+datetime.timedelta(offset)
将年份传递给该函数,它将返回第一个星期二作为datetime
对象。
答案 1 :(得分:1)
在这里,您有一个非常简单的python函数,可以将每个月的第一年的星期二定为一年。
import datetime as dt
def first_tuesday_of_month(year, month):
d = dt.datetime(year, month, 1)
wd = d.weekday()
# monday
if wd == 0:
return 2
# tuesday
if wd == 1:
return 1
# wensday
if wd == 2:
return 7
# thursday
if wd == 3:
return 6
# friday
if wd == 4:
return 5
# saturday
if wd == 5:
return 4
# sunday 6
if wd == 6:
return 3
if __name__ == "__main__":
print(first_tuesday_of_month(2020, 6))
print(first_tuesday_of_month(2020, 1))
print(first_tuesday_of_month(2020, 2))
print(first_tuesday_of_month(2021, 6))
输出
D:\workspace\stackoverflow\python>python first_tuesday_of_month.py
2
7
4
1