Question

我在购物车视图页面上有产品面板，用户可以点击每个产品上的编辑链接按钮来编辑产品详细信息，但业务规则要求购物车一旦绑定，这意味着提交的状态字段该提交的表格从“新”更新为“绑定”，用户无法再编辑其产品。我一直在尝试一些不同的方法来禁用链接按钮（switchcase，如果那时等），但无济于事。有没有一种简单的方法可以将条件传递给linkbutton代码，使其可见性/启用属性以该表字段为条件？代码如下：

当我运行此块时，链接按钮仍然可见（如果我将其设置为.visible = false）和/或启用。 ??

string product = "SELECT ProductId FROM SubmissionProducts WHERE SubmissionId =" + x;
    using (SqlConnection editConn = new SqlConnection(connectionString))
    {
        editConn.Open();
        using (SqlCommand comntCmd = new SqlCommand(comnt, editConn))
        {
            SqlDataReader dr = comntCmd.ExecuteReader();
            dr.Read();
            var c = dr.GetInt32(0);
            if (c > 0)
            {
                PanelQuote.Visible = false;
                using (SqlCommand prodcmd = new SqlCommand(product, editConn))
                {
                    SqlDataReader drpan = prodcmd.ExecuteReader();
                    while (dr.Read())
                        switch (drpan.GetInt32(0))
                        {
                            case 1:
                                LnbEpl.Enabled = false;
                                break;
                            case 2:
                                LnbFid.Enabled = false;
                                break;
                            case 3:
                                LnbCrim.Enabled = false;
                                break;
                            case 4:
                                LnbPub.Enabled = false;
                                break;
                            case 5:
                                LnbPriv.Enabled = false;
                                break;
                            case 6:
                                LnbNot.Enabled = false;
                                break;
                            case 7:
                                LnbEo.Enabled = false;
                                break;
                            default:
                                break;
                        }
                }

            }
            else
                PanelComment.Visible = false;
        }

Answer 1

这样做，我改变了几件事，删除whiles并创建新连接，因为您提供的代码将抛出此异常"There is already an open DataReader associated with this Command which must be closed first."

SqlConnection editConn1 = new SqlConnection(connectionString);
SqlConnection editConn2 = new SqlConnection(connectionString);
editConn1.Open();
editConn2.Open();

SqlCommand comntCmd = new SqlCommand(comnt, editConn1);
SqlDataReader dr = comntCmd.ExecuteReader();
dr.Read();
var c = dr.GetInt32(0);
if (c > 0)
{
    PanelQuote.Visible = false;
    SqlCommand prodcmd = new SqlCommand(product, editConn2);
    SqlDataReader drpan = prodcmd.ExecuteReader();
    drpan.Read();
    var d = drpan.GetInt32(0);
    switch (d)
    {
        case 1:
            LnbEpl.Enabled = false;
            break;
        case 2:
            LnbFid.Enabled = false;
            break;
        case 3:
            LnbCrim.Enabled = false;
            break;
        case 4:
            LnbPub.Enabled = false;
            break;
        case 5:
            LnbPriv.Enabled = false;
            break;
        case 6:
            LnbNot.Enabled = false;
            break;
        case 7:
            LnbEo.Enabled = false;
            break;
        default:
            break;
    }
}
else
{
    PanelComment.Visible = false;
}

当table field = x时禁用链接按钮？

1 个答案: