获取按日期分组的查询

Question

我有这些表：

server ocurrences date
A      122        20200101
B      1          20200101
C      15         20200101
............

我很想得到这些结果：

                A;B;C
20200101        122;1;15

我进行以下查询：

select server, ocurrences, date FROM NET_REPORT 
where to_char(date,'YYYYMMDD') >= '20200101' 
AND server IN ('A','B','C') GROUP BY date, server,ocurrences ORDER BY date,server;

但是我无法获得想要的东西。 请问你能帮帮我吗？ 谢谢

Answer 1

我认为您想要string_agg()或array_agg()。我强烈推荐后者：

select date, array_agg(server) as servers,
       array_agg(ocurrences) as occurrences
from net_report 
where date >= '2020-01-01' and
      date < '2020-01-02' and
      server in ('des', 'pre', 'prod') 
group by date
order by date;