查询ManyToMany关系Django

Question

嘿，我想从数据库中查询manyToManyField的每个人似乎都行不通。我想从数据库模型中获取所有框架不兼容的列表。但是当我进行查询时，我什么也没得到。

这是我的模特：

class Framework(models.Model):
    name = models.CharField(max_length=200)
    language = models.ManyToManyField(Language)
    version = models.CharField(max_length=20)
    typeOfFramework = models.ForeignKey(TypeOfProgram, on_delete=models.CASCADE)
    pros = models.ManyToManyField(Pro)
    nombreAvantage = models.IntegerField(default = 0)
    cons = models.ManyToManyField(Con)
    nombreDesavantage = models.IntegerField(default = 0)
    additionalInformation =  models.ForeignKey(web,blank=True,null=True ,default = None ,on_delete=models.CASCADE)
    incompatibility = models.ManyToManyField("self",blank=True)

    def __str__(self):
        template = '{0.name} {0.version} {0.typeOfFramework} {0.nombreAvantage} {0.nombreDesavantage} {0.additionalInformation}'
        return template.format(self)

    def getLanguage(self):
        return ", ".join([p.name for p in self.language.all()])
    def getPros(self):
        return ", ".join([p.advantage for p in self.pros.all()])
    def getCons(self):
        return ", ".join([p.disadvantage for p in self.cons.all()])

    def getIncompatibility(self):
        return ", ".join([(p.name + ' '+ p.version) for p in self.incompatibility.all()])


    def __iter__(self):
        return [ self.name, 
                 self.language,
                 self.version, 
                 self.typeOfFramework,  
                 self.pros, 
                 self.cons, 
                 self.additionalInformation
      ]

class DataPro(models.Model):
    advantage = models.CharField(max_length=200)
    def __str__(self):
        template = '{0.advantage}'
        return template.format(self)

class DataCon(models.Model):
    disadvantage = models.CharField(max_length=200)
    def __str__(self):
        template = '{0.disadvantage}'
        return template.format(self)

class Database(models.Model):
    name = models.CharField(max_length=200)
    version = models.CharField(max_length=20)
    pros = models.ManyToManyField(DataPro)
    nombreAvantage = models.IntegerField(default = 0)
    cons = models.ManyToManyField(DataCon)
    nombreDesavantage = models.IntegerField(default = 0)
    frameworkIncompatibility = models.ManyToManyField(Framework, blank=True)
    def __str__(self):
        template = '{0.name} {0.version} {0.nombreAvantage} {0.nombreDesavantage}'
        return template.format(self)

    def getDataPros(self):
        return ", ".join([p.advantage for p in self.pros.all()])
    def getDataCons(self):
        return ", ".join([p.disadvantage for p in self.cons.all()])
    def getFrameworkIncompatibility(self):
        return ", ".join([p.name + " "+ p.version for p in self.frameworkIncompatibility.all()])

这是我要获取

列表的视图

            listOfDatabase = Database.objects.values_list()
            databaseIncompatibility = []
            for s in listOfDatabase:
                databaseIncompatibility.append(s.objects.filter(frameworkIncompatibility__in=Framework.objects.all()))



            listDatabase = [(q[0],q[1],q[2],q[3],q[4])for q in listOfDatabase]
            #ID, name, version, con, pro

很抱歉，如果这是一个愚蠢的问题，那是我的第一个django项目，我对如何做一些事情有些迷茫。

谢谢大家的回答。