API请求未给出响应

时间:2020-02-24 02:39:17

标签: ios swift alamofire

我正在尝试使用(https://collegescorecard.ed.gov/data/documentation/)来填充ios应用程序中的表,但是没有任何数据显示。我已经尝试了很多次api键和url,所以我不这么认为。 json文件的结构

Dev类学校

名称字符串 IPEDS中报告的机构名称(INSTNM)。

import UIKit
import Alamofire

class ViewController: UIViewController {
    let URLStr = "https://api.data.gov/ed/collegescorecard/v1/schools?fields=school.name"

    var resultArray = [Users]()
    @IBOutlet weak var tableView: UITableView!
    @IBOutlet weak var searchBar: UISearchBar!
     var searchCollege = [String]()

override func viewDidLoad() {
         super.viewDidLoad()
         tableView.dataSource = self
         tableView.delegate = self
         callAPI()


            }
    override func didReceiveMemoryWarning() {
           super.didReceiveMemoryWarning()
       }

func callAPI() {
        let key = "key redacted"
        //let url = URL(string:"\(URLStr)?api_key=\(key)")
        let url = URL(string:"\(URLStr)&api_key=\(key)")
        print(url)
        Alamofire.request(url!, method: .get, parameters: nil, headers:[:]).responseJSON {(response) in
            if let responseObj = response.value as? [[String: Any]]{
                self.resultArray = self.parseJSON(userData: responseObj)
                print("response here", response)
                self.tableView.reloadData()
                }
        }

}
func parseJSON(userData: [[String:Any]])-> [Users] {
    var userArr = [Users]()
    for obj in userData {
        do { let data = try JSONSerialization.data(withJSONObject: obj, options: .prettyPrinted)
            let decodedData = try JSONDecoder().decode(Users.self, from: data)
            userArr.append(decodedData)
            }

    catch {

        }
    }
        return userArr
    }
}

userModal.swift

mport Foundation
struct Users: Codable {
    let userSchool_name: String?
}
enum CodingKeys: String, CodingKey {
    case userSchool_name = "school.name"
}

我试图打印出响应和不同的对象,但是什么也没打印出来。我下面有一个函数可以在应用程序中显示它,但我认为这不是问题。

json输出

SUCCESS: {
    metadata =     {
        page = 0;
        "per_page" = 20;
        total = 7112;
    };
    results =     (
                {
            "school.name" = "West Michigan College of Barbering and Beauty";
        },
                {
            "school.name" = "Georgia College & State University";
        },
                {
            "school.name" = "Georgia Southern University";
        },
                {
            "school.name" = "Clayton  State University";
        },
                {
            "school.name" = "Andrew College";
        },
                {
            "school.name" = "Columbus Technical College";
        },
                {
            "school.name" = "Georgia Northwestern Technical College";
        },
                {
            "school.name" = "Atlanta Metropolitan State College";
        },
                {
            "school.name" = "Clark Atlanta University";
        },
                {
            "school.name" = "Augustana College";
        },
                {
            "school.name" = "Miami Ad School at Portfolio Center";
        },
                {
            "school.name" = "Tricoci University of Beauty Culture-Urbana";
        },
                {
            "school.name" = "University of Hawaii at Manoa";
        },
                {
            "school.name" = "Aveda Institute-Twin Falls";
        },
                {
            "school.name" = "Cameo Beauty Academy";
        },
                {
            "school.name" = "Truett McConnell University";
        },
                {
            "school.name" = "Cannella School of Hair Design-Chicago";
        },
                {
            "school.name" = "Valdosta State University";
        },
                {
            "school.name" = "American Academy of Art";
        },
                {
            "school.name" = "City Colleges of Chicago-Kennedy-King College";
        }
    );
}

1 个答案:

答案 0 :(得分:0)

首先删除parseJSON,将JSON转换为数组,然后再转换回JSON,然后再转换为带有JSONDecoder的结构是没有意义的

func parseJSON(userData: [[String:Any]])-> [Users] {
var userArr = [Users]()
for obj in userData {
    do { let data = try JSONSerialization.data(withJSONObject: obj, options: .prettyPrinted)
        let decodedData = try JSONDecoder().decode(Users.self, from: data)
        userArr.append(decodedData)
        }

catch {

    }
}
    return userArr
}
}  

然后您必须为根对象添加一个结构

struct Root: Codable {
    let results : [Users]
}

struct Users: Codable {
    let userSchool_name: String?

     private enum CodingKeys: String, CodingKey {
        case userSchool_name = "school.name"
     }
}

并用

替换Alamofire零件
   Alamofire.request(url!).responseData { response in
        switch response.result {
            case .success(let data):
                do {
                    self.resultArray = try JSONDecoder().decode(Root.self, from: data).results
                    self.tableView.reloadData()
                } catch {
                    print(error)
            }
            case .failure(let error):
                print(error)
        }
    }

它接收Data而不是解码的数组并处理所有错误。