Question

一个简单的问题-在bokeh中，您可以绘制半径而不是大小的圆，以便在放大或缩小时调整圆。是否可以使用基于holoviews的散点图来进行此操作-目前尚无设置半径的选项，也无法解决如何以其他方式（例如渲染）提供半径的问题。可能是用户错误，所以在此先致歉，谢谢。

import holoviews as hv
hv.extension('bokeh')
from bokeh.plotting import figure, show
x=(1,2,3)
y=(1,2,3)
p=figure()
p.scatter(x, y, radius=0.2)
show(p) # bokeh plot working as expected
scatter=hv.Scatter((x,y)).opts(marker="circle", size=20)
scatter # holoviews plot, cannot code "radius" for code above - causes error.

Answer 1

所有hv.Scatter图都基于Bokeh的Scatter标记，该标记的文档字符串中包含以下部分：

Note that circles drawn with `Scatter` conform to the standard Marker
interface, and can only vary by size (in screen units) and *not* by radius
(in data units). If you need to control circles by radius in data units,
you should use the Circle glyph directly.

这意味着您不能使用hv.Scatter，而必须使用其他内容：

import holoviews as hv
import param
from holoviews.element.chart import Chart
from holoviews.plotting.bokeh import PointPlot

hv.extension('bokeh')

x = (1, 2, 3)
y = (1, 2, 3)


class Circle(Chart):
    group = param.String(default='Circle', constant=True)

    size = param.Integer()


class CirclePlot(PointPlot):
    _plot_methods = dict(single='circle', batched='circle')

    style_opts = ['radius' if so == 'size' else so for so in PointPlot.style_opts if so != 'marker']


hv.Store.register({Circle: CirclePlot}, 'bokeh')

scatter = Circle((x, y)).opts(radius=0.5)

如何在全息视图中设置散点圆半径？

1 个答案: