Question

我一直在遇到do while循环不重复的问题。当提示再次添加两个数字时我选择N时，它将按预期退出程序，但是选择Y或y会使程序挂起，将我带到下一行，但使我无法键入任何内容。如果您能帮助我，我将不胜感激。谢谢！

#include <iostream>
using namespace std;
int main()
{

int number1, number2; //Two numbers
int sum;              //Sum
char again;     //For yet another attempt


{  //Inputting the two numbers

    cout << "\nEnter two numbers, and i will add them: ";
    cin >> number1 >> number2;

    //Adding the two numbers

    sum = number1 + number2;
    cout << "The sum of the two numbers you have picked is " << sum << "\n\n";

    //Does the user want to add two other numbers?
    cout << "Do you want to add two other numbers? (Y/N) ";
    cin >> again;
}
    while (again == ('y') || again == ('Y'));


   return 0;
}

Answer 1

do { statement} while(condition)

在上面的循环语法中执行，我想您在语法方面错过了世界。尝试替换您的do-while阻止，如下所示。

do{  //Inputting the two numbers

cout << "\nEnter two numbers, and i will add them: ";
cin >> number1 >> number2;

//Adding the two numbers

sum = number1 + number2;
cout << "The sum of the two numbers you have picked is " << sum << "\n\n";

//Does the user want to add two other numbers?
cout << "Do you want to add two other numbers? (Y/N) ";
cin >> again;}while (again == ('y') || again == ('Y'));

Answer 2

是的，您需要在一段时间内执行一次。不能说比lion_pankaj好。

每次在运行程序之前向代码添加新内容或进行调试时，还应进行构建检查，并检查所有警告或错误（如果有）。还取决于用来帮助发现少量错误的IDE。有时我们都会忘记一点东西。

“ do while”循环挂起，不重复

2 个答案: